
Concept explainers
Can a particle ever move from a region of low electric potential to one of high potential and yet have its electric potential energy decrease?

Answer to Problem 5Q
Solution:
A particle can move from a region of low electric potential to one of high potential and yet have its electric potential energy decrease
Explanation of Solution
We have potential difference between two points, , where is the potential energy and q is the charge.
Now consider a negative charge is released, it will move towards positive plate. Because of the acceleration of the charge its kinetic energy increases. When kinetic energy increases potential energy decreases. i.e. and , so potential difference between 2 points is positive. Which means negative charge moves to a region of higher potential. So, a particle can move from a region of low electric potential to one of high potential and yet have its electric potential energy decrease.
Chapter 17 Solutions
Physics: Principles with Applications
Additional Science Textbook Solutions
Human Anatomy & Physiology (2nd Edition)
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Anatomy & Physiology (6th Edition)
Microbiology: An Introduction
Genetic Analysis: An Integrated Approach (3rd Edition)
Microbiology with Diseases by Body System (5th Edition)
- Hi! I need help with these calculations for part i and part k for a physics Diffraction Lab. We used a slit width 0.4 mm to measure our pattern.arrow_forwardExamine the data and % error values in Data Table 3 where the angular displacement of the simple pendulum decreased but the mass of the pendulum bob and the length of the pendulum remained constant. Describe whether or not your data shows that the period of the pendulum depends on the angular displacement of the pendulum bob, to within a reasonable percent error.arrow_forwardIn addition to the anyalysis of the graph, show mathematically that the slope of that line is 2π/√g . Using the slope of your line calculate the value of g and compare it to 9.8.arrow_forward
- An object is placed 24.1 cm to the left of a diverging lens (f = -6.51 cm). A concave mirror (f= 14.8 cm) is placed 30.2 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?arrow_forwardConcept Simulation 26.4 provides the option of exploring the ray diagram that applies to this problem. The distance between an object and its image formed by a diverging lens is 5.90 cm. The focal length of the lens is -2.60 cm. Find (a) the image distance and (b) the object distance.arrow_forwardPls help ASAParrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





