Chapter 17, Problem 56P

Interpretation Introduction

(a)

Interpretation:

The ester formed on treating 2-propanol with CH₃CH₂COOH in the presence of H₂SO₄ should be determined.

Concept Introduction:

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

Answer to Problem 56P

  

Explanation of Solution

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

The general reaction is written as:

  $\begin{array}{l}\text{RCOOH}{\text{+R}}^{\text{'}}\text{OH}\stackrel{{\text{Δ, H}}^{+}}{\to }{\text{RCOOR}}^{\text{'}}\text{+}{\text{H}}_{\text{2}}\text{O}\\ \text{Acid}\text{Alcohol}\text{Ester}\text{water}\end{array}$

Thus, the reaction between CH₃CH₂COOH (propanoic acid) and 2-propanol is:

  

Interpretation Introduction

(b)

Interpretation:

The ester formed on treating 2-propanol with following in the presence of H₂SO₄ should be determined:

  

Concept Introduction:

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

Answer to Problem 56P

  

Explanation of Solution

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

The general reaction is written as:

  $\begin{array}{l}\text{RCOOH}{\text{+R}}^{\text{'}}\text{OH}\stackrel{{\text{Δ, H}}^{+}}{\to }{\text{RCOOR}}^{\text{'}}\text{+}{\text{H}}_{\text{2}}\text{O}\\ \text{Acid}\text{Alcohol}\text{Ester}\text{water}\end{array}$

Thus, the reaction between CH₃(CH₂)₁₀COOH (dodoecanoic acid) and 2-propanol is:

  

Interpretation Introduction

(c)

Interpretation:

The ester formed on treating 2-propanol with HCO₂H in the presence of H₂SO₄ should be determined.

Concept Introduction:

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

Answer to Problem 56P

  

Explanation of Solution

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

The general reaction is written as:

  $\begin{array}{l}\text{RCOOH}{\text{+R}}^{\text{'}}\text{OH}\stackrel{{\text{Δ, H}}^{+}}{\to }{\text{RCOOR}}^{\text{'}}\text{+}{\text{H}}_{\text{2}}\text{O}\\ \text{Acid}\text{Alcohol}\text{Ester}\text{water}\end{array}$

Thus, the reaction between HCO₂H (formic acid) and 2-propanol is:

  

Interpretation Introduction

(d)

Interpretation:

The ester formed on treating 2-propanol with following in the presence of H₂SO₄ should be determined:

  

Concept Introduction:

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

Answer to Problem 56P

  

Explanation of Solution

The reaction which results in the formation of at least one ester along with water on heating acids with alcohols is said to be esterification.

The general reaction is written as:

  $\begin{array}{l}\text{RCOOH}{\text{+R}}^{\text{'}}\text{OH}\stackrel{{\text{Δ, H}}^{+}}{\to }{\text{RCOOR}}^{\text{'}}\text{+}{\text{H}}_{\text{2}}\text{O}\\ \text{Acid}\text{Alcohol}\text{Ester}\text{water}\end{array}$

Thus, the reaction between 4-methoxybenzoic acid and 2-propanol is: