Chapter 17, Problem 41E

To determine

To explain: it's very rare for him to make minimum 32 of 40 shots.

Answer to Problem 41E

0.06 percent

Explanation of Solution

Given:

  $\begin{array}{c}p=0.55\\ n=40\end{array}$

Formula used:

  $P\left(X=r\right)=C{}_r{\left(p\right)}^r{\left(1-p\right)}^{n-r}$

Calculation:

The problem-related data is that the total number of shots is 40, the chance of the basketball player hitting his free throw is 0.55.

Let X is the number of shots are successful.

Required probability is

  $\begin{array}{c}P\left(X\ge 32\right)=C{}_{32}{\left(0.55\right)}^{32}{\left(0.45\right)}^8\\ =0.000636\end{array}$

There is 0.06 percent possibility that researcher makes minimum 32 out of 40 shots.

It is very unusual.