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(a)
To Explain: that these circumstances having Bernoulli trials that roll out 50 dice to get the number of spots on the face’s distribution.
(a)
Explanation of Solution
There are more than two possible results per trial − there are 6 possible outcomes (each face of the die may be present). The distribution of the number of spots over the face of the dice cannot be identified in Bernoulli 's experiments.
(b)
To Explain: that these circumstances having Bernoulli trials that how possible is the majority to have blood type A in a population of 120 on the basis of given information.
(b)
Explanation of Solution
Bernoulli trials can be used to assess how often the majority of 120 participants in a population have Type A blood, provided that 43% have Type A blood. Two possible impacts exist (one person either has or doesn't have blood Type A), there is a continuous chance of success (43 percent of people have blood Type A) and trials are separate (where one of the individuals has blood Type A depends entirely on whether the others have blood Type A).
(c)
To Explain: that these circumstances having Bernoulli trials that deal seven card from the deck and getting the all hearts.
(c)
Explanation of Solution
Bernoulli trials cannot be used to assess how likely 7 cards picked randomly from a deck all are to be heart since the trials are not separate. Whenever a card is drawn, the other deck will change and the odds will change the next deck.
(d)
To Explain: that these circumstances having Bernoulli trials that wish to project the effect of a vote on the school budget, and to see how many supports the budget suggested by 500 of the 3000 likely to vote.
(d)
Explanation of Solution
Bernoulli trials cannot be used to vote 500 out of the 3000 electors to calculate the possibility of a bill being passed because 500 is over 10 percent out of 3000.
(e)
To Explain: that these circumstances having Bernoulli trials that an organisation recognises that about 10% of the packages are not correctly packed.
(e)
Explanation of Solution
When 10 percent of the packages are unscreened and the packets are in 24 cases, it will use Bernoulli checks to see how many more than 3 packets are unsealed in 24 cases, as long as the packages are unsealed.
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