Physics
Physics
3rd Edition
ISBN: 9780073512150
Author: Alan Giambattista, Betty Richardson, Robert C. Richardson Dr.
Publisher: McGraw-Hill Education
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Chapter 17, Problem 34P

(a)

To determine

The electric force on the particle.

(a)

Expert Solution
Check Mark

Answer to Problem 34P

The electric force on the particle is 1.0μN directed to the right.

Explanation of Solution

The magnitude of the electric field is 240NC1 directed to the right and the charge of the particle is +4.2nC.

Write the expression for electric force

    F=qE                                                                                                                       (I)

Here, F is the electric force, q is the charge of the particle and E is the electric field. The direction of electric force is same as the direction of the electric field.

Substitute 240NC1 for E and +4.2 nC for q in (I) to find F

  F=(+4.2 nC)(240NC1)=(+4.2×109 C)(240NC1)=1.0×106N=1.0μN

Thus, the electric force is 1.0μN directed to the right.

(b)

To determine

The potential difference along a straight line from path a to b.

(b)

Expert Solution
Check Mark

Answer to Problem 34P

The potential difference is 60V.

Explanation of Solution

Electric field is the negative gradient of potential and hence points in the direction of decreasing potential.

Physics, Chapter 17, Problem 34P

The potential at point b is lesser than the potential at point a.

Write the expression for potential difference if the particle moves in a straight line from a to b

    ΔV=VbVa=Ed                                                                                                  (II)

Here, ΔV is the potential difference, Va is the potential at point a, Vb is the potential at point b, E is the magnitude of electric field and d is the distance between point a and b.

Substitute 240NC1 for E and 0.25m for d in (II) to find ΔV.

  ΔV=(240NC1)(0.25m)=60V

Thus, the potential difference is 60V.

(c)

To determine

The change in electric potential energy of the particle.

(c)

Expert Solution
Check Mark

Answer to Problem 34P

The change in electric potential energy of the particle is 0.25μJ.

Explanation of Solution

The charge being moved is +4.2nC.

Write the expression for change in electric potential energy

  ΔU=qΔV                                                                                                          (III)

Here, ΔU is the change in electric potential energy, q is the charge being moved from the point a to b.

Substitute  +4.2nC for q and 60V for ΔV in (III) to find ΔU

    ΔU=+4.2nC[60V]3=+4.2×109C(60V)=0.25×106J0.25μJ

Thus, the change in electric potential energy is 0.25μJ.

(d)

To determine

The work done on the particle by the electric field.

(d)

Expert Solution
Check Mark

Answer to Problem 34P

The work done by the electric field is 0.25μJ.

Explanation of Solution

Write the expression for work done by the electric field in terms of force and displacement

  W=Fdcosθ                                                                                                      (IV)

Here, W is the work done by the electric field, F is the magnitude of the electric force, d is the distance between the points a and b whereas θ is the angle between the force and the displacement vector.

Since force and the displacement vector is along the same direction in the given path,θ=0°

Substitute 1.0μN for F, 0° for θ and 0.25m for d in (IV) to find W

  W=1.0μN(0.25m)cos0°=0.25×106Nm1×1=0.25μJ

Write the expression for work done by the electric field in moving a charge

  W=ΔU                                                                                                             (V)

Here, W is the work done by the electric field and ΔU is the change in electric potential in moving the charge from a to b.

Substitute 0.25μJ for ΔU in (V) to find W

    W=(0.25μJ)=0.25μJ

The result using (IV) and (V) are the same.

Thus, the work done by the electric field is 0.25μJ.

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Chapter 17 Solutions

Physics

Ch. 17.4 - Prob. 17.8PPCh. 17.5 - Prob. 17.5CPCh. 17.5 - Prob. 17.9PPCh. 17.6 - Prob. 17.6CPCh. 17.6 - Prob. 17.10PPCh. 17.6 - Prob. 17.11PPCh. 17.7 - Practice Problem 17.12 Charge and Stored Energy...Ch. 17 - Prob. 1CQCh. 17 - 2. Dry air breaks down for a voltage of about 3000...Ch. 17 - 3. A bird is perched on a high-voltage power line...Ch. 17 - 4. A positive charge is initially at rest in an...Ch. 17 - 5. Points A and B are at the same potential. What...Ch. 17 - Prob. 6CQCh. 17 - 7. Why are all parts of a conductor at the same...Ch. 17 - Prob. 8CQCh. 17 - Prob. 9CQCh. 17 - Prob. 10CQCh. 17 - Prob. 11CQCh. 17 - Prob. 12CQCh. 17 - Prob. 13CQCh. 17 - Prob. 14CQCh. 17 - Prob. 15CQCh. 17 - Prob. 16CQCh. 17 - Prob. 17CQCh. 17 - Prob. 18CQCh. 17 - Prob. 19CQCh. 17 - Prob. 20CQCh. 17 - Prob. 21CQCh. 17 - Prob. 22CQCh. 17 - Prob. 1MCQCh. 17 - Prob. 2MCQCh. 17 - Prob. 3MCQCh. 17 - Prob. 4MCQCh. 17 - Prob. 5MCQCh. 17 - Prob. 6MCQCh. 17 - Prob. 7MCQCh. 17 - Prob. 8MCQCh. 17 - Prob. 9MCQCh. 17 - Prob. 10MCQCh. 17 - Prob. 11MCQCh. 17 - Prob. 12MCQCh. 17 - 1. In each of five situations, two point charges...Ch. 17 - 2. Two point charges, +5.0 μC and −2.0 μC, are...Ch. 17 - 3. A hydrogen atom has a single proton at its...Ch. 17 - 4. How much work is done by an applied force that...Ch. 17 - 5. The nucleus of a helium atom contains two...Ch. 17 - 6. Three point charges are located at the corners...Ch. 17 - Problems 7-10. Two point charges ( + 10.0 nC and −...Ch. 17 - Problems 7-10. Two point charges ( + 10.0 nC and −...Ch. 17 - Problems 7-10. Two point charges ( + 10.0 nC and −...Ch. 17 - Problems 7–10. Two point charges ( +10.0 nC and...Ch. 17 - 11. Find the electric potential energy for the...Ch. 17 - 12. In the diagram, how much work is done by the...Ch. 17 - 13. In the diagram, how much work is done by the...Ch. 17 - Prob. 14PCh. 17 - Prob. 15PCh. 17 - 16. A point charge q = + 3.0 nC moves through a...Ch. 17 - 17. An electron is moved from point A, where the...Ch. 17 - 18. Find the electric field and the potential at...Ch. 17 - Prob. 19PCh. 17 - 20. A charge of + 2.0 mC is located at x = 0, y =...Ch. 17 - 21. The electric potential at a distance of 20.0...Ch. 17 - 22. A spherical conductor with a radius of 75.0 cm...Ch. 17 - 23. A hollow metal sphere carries a charge of 6.0...Ch. 17 - 24. An array of four charges is arranged along the...Ch. 17 - 25. At a point P, a distance R0 from a positive...Ch. 17 - 26. Charges of + 2.0 nC and − 1.0 nC are located...Ch. 17 - Prob. 27PCh. 17 - 28. (a) Find the potential at points a and b in...Ch. 17 - 29. (a) In the diagram, what are the potentials at...Ch. 17 - 30. (a) In the diagram, what are the potentials at...Ch. 17 - Prob. 31PCh. 17 - 32. By rewriting each unit in terms of kilograms,...Ch. 17 - 33. Rank points A–E in order of the potential,...Ch. 17 - Prob. 34PCh. 17 - Prob. 35PCh. 17 - Prob. 36PCh. 17 - Prob. 37PCh. 17 - Prob. 38PCh. 17 - Prob. 39PCh. 17 - Prob. 40PCh. 17 - Prob. 41PCh. 17 - Prob. 42PCh. 17 - 43. A positive point charge is located at the...Ch. 17 - Prob. 44PCh. 17 - Prob. 45PCh. 17 - 46. Point P is at a potential of 500.0 kV, and...Ch. 17 - 47. An electron is accelerated from rest through a...Ch. 17 - 48. As an electron moves through a region of...Ch. 17 - Prob. 49PCh. 17 - 50. An electron beam is deflected upward through...Ch. 17 - 51. In the electron gun of Example 17.8, if the...Ch. 17 - 52. In the electron gun of Example 17.8, if the...Ch. 17 - 53. An electron (charge −e) is projected...Ch. 17 - 54. An alpha particle (charge +2e) moves through a...Ch. 17 - 55. In 1911, Ernest Rutherford discovered the...Ch. 17 - 56. The figure shows a graph of electric potential...Ch. 17 - 57. Repeat Problem 56 for an electron rather than...Ch. 17 - 58. A 2.0 μE capacitor is connected to a 9.0 V...Ch. 17 - 59. The plates of a 15.0 μE capacitor have net...Ch. 17 - 60. If a capacitor has a capacitance of 10.2 μE...Ch. 17 - 61. A parallel plate capacitor has a capacitance...Ch. 17 - 62. A parallel plate capacitor has plates of area...Ch. 17 - 63. A parallel plate capacitor has plates of area...Ch. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Prob. 66PCh. 17 - Prob. 67PCh. 17 - Prob. 68PCh. 17 - Prob. 69PCh. 17 - Prob. 70PCh. 17 - Prob. 71PCh. 17 - Prob. 72PCh. 17 - Prob. 73PCh. 17 - Prob. 74PCh. 17 - Prob. 75PCh. 17 - Prob. 76PCh. 17 - Prob. 77PCh. 17 - 78. What is the maximum electric energy density...Ch. 17 - Prob. 79PCh. 17 - Prob. 80PCh. 17 - Prob. 81PCh. 17 - Prob. 82PCh. 17 - Prob. 83PCh. 17 - 84. A parallel plate capacitor is composed of two...Ch. 17 - Prob. 85PCh. 17 - 86. A parallel plate capacitor has a charge of...Ch. 17 - Prob. 87PCh. 17 - Prob. 88PCh. 17 - Prob. 89PCh. 17 - Prob. 90PCh. 17 - Prob. 91PCh. 17 - Prob. 92PCh. 17 - Prob. 93PCh. 17 - Prob. 94PCh. 17 - Prob. 95PCh. 17 - Prob. 96PCh. 17 - Prob. 97PCh. 17 - Prob. 98PCh. 17 - Prob. 99PCh. 17 - Prob. 100PCh. 17 - Prob. 101PCh. 17 - Prob. 102PCh. 17 - Prob. 103PCh. 17 - Prob. 104PCh. 17 - Prob. 105PCh. 17 - 106. ✦ The potential difference across a cell...Ch. 17 - Prob. 107PCh. 17 - Prob. 108PCh. 17 - Prob. 109PCh. 17 - Prob. 110PCh. 17 - Prob. 111PCh. 17 - Prob. 112PCh. 17 - Prob. 113PCh. 17 - Prob. 114PCh. 17 - Prob. 115PCh. 17 - Prob. 116PCh. 17 - Prob. 117PCh. 17 - Prob. 118PCh. 17 - Prob. 119PCh. 17 - Prob. 120PCh. 17 - Prob. 121P
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