Materials Science And Engineering
10th Edition
ISBN: 9781119405498
Author: Callister, William D., Jr, RETHWISCH, David G., Jr., 1940- Author.
Publisher: Wiley,
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Question
Chapter 17, Problem 2DP
(a)
To determine
To suggest:
An appropriate material for the following applications, and, if necessary recommend corrosion prevention measures.
Laboratory bottles to contain relatively dilute solutions of nitric acid.
(b)
To determine
To suggest:
An appropriate material for the following applications, and, if necessary recommend corrosion prevention measures.
Barrels to contain benzene:
(c)
To determine
To suggest:
An appropriate material for the following applications, and, if necessary recommend corrosion prevention measures.
Pipe to transport hot alkaline (basic) solutions:
(d)
To determine
To suggest:
An appropriate material for the following applications, and, if necessary recommend corrosion prevention measures.
Underground tanks to store large quantities of high-purity water:
(e)
To determine
To suggest:
An appropriate material for the following applications, and, if necessary recommend corrosion prevention measures.
Architectural trim for high-rise buildings:
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Using the 802.11a specifications given below, in Matlab (or similar tool) create the time domain signal
for one OFDM symbol using QPSK modulation. See attached plot for the QPSK constellation.
Your results should include the power measure in the time and frequency domain and comment on
those results.
BW
802.11a OFDM PHY Parameters
20 MHZ
OBW
Subcarrer Spacing
Information Rate
Modulation
Coding Rate
Total Subcarriers
Data Subcarriers
Pilot Subcarriers
DC Subcarrier
16.6 MHZ
312.5 Khz (20MHz/64 Pt FFT)
6/9/12/18/24/36/48/54 Mbits/s
BPSK, QPSK, 16QAM, 64QAM
1/2, 2/3, 3/4
52 (Freq Index -26 to +26)
48
4 (-21, -7, +7, +21)
*Always BPSK
Null (0 subcarrier)
52 subarriers
-7
(48 Data, 4 Pilot (BPSK), 1 Null)
-26 -21
0
7
21 +26
14
One Subcarrier
1 OFDM symbol
1 OFDM Burst
-OBW 16.6 MHz
BW 20 MHZ
1 constellation point
= 52 subcarriers
= one or more OFDM symbols
802.11a OFDM Physical Parameters
Show signal at this point
x bits
do
Serial
Data
d₁
S₁
Serial-to-
Input
Signal
Parallel
Converter
IFFT…
Find Vb and Va using Mesh analysis
1. The communication channel bandwidth is 25 MHz centered at 1GHz and has a noise power spectral
density of 10^-9 W/Hz. The channel loss between the transmitter and receiver is 25dB. The application
requires a bit rate of 200Mbps and BER of less than 10^-4. Excluding Mary FSK, Determine the minimum
transmit power required.
Chapter 17 Solutions
Materials Science And Engineering
Ch. 17 - Prob. 1QAPCh. 17 - Prob. 2QAPCh. 17 - Prob. 3QAPCh. 17 - Prob. 4QAPCh. 17 - Prob. 10QAPCh. 17 - Prob. 13QAPCh. 17 - Prob. 15QAPCh. 17 - Prob. 16QAPCh. 17 - Prob. 19QAPCh. 17 - Prob. 20QAP
Ch. 17 - Prob. 21QAPCh. 17 - Prob. 22QAPCh. 17 - Prob. 23QAPCh. 17 - Prob. 24QAPCh. 17 - Prob. 25QAPCh. 17 - Prob. 26QAPCh. 17 - Prob. 27QAPCh. 17 - Prob. 29QAPCh. 17 - Prob. 31QAPCh. 17 - Prob. 32QAPCh. 17 - Prob. 1DPCh. 17 - Prob. 2DPCh. 17 - Prob. 3DPCh. 17 - Prob. 1FEQPCh. 17 - Prob. 2FEQPCh. 17 - Prob. 3FEQP
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Similar questions
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- No chatgpt plsarrow_forward11. The prestressed T beam shown below is pretensioned using low relaxation stress-relieved Grade 270 strands. The steel area Aps = 2.5 in². The tensile strength is fpu = 270 ksi, and the concrete compressive strength is fr = 6000 psi. (a) Calculate the nominal moment strength Mn with hr = 6 in. 22" 15" T hf (b) Since this beam is a T-beam, the nominal moment strength M₁ increases with a thicker hf. However, M, stops increasing if he reaches a value. Determine the minimum thickness hy that can achieve the maximum nominal moment strength Mr. Also, calculate the corresponding maximum nominal moment strength Mn with the computed hf.arrow_forward10. A short column is subjected to an eccentric loading. The axial load P = 1000 kips and the eccentricity e = 12 in. The material strengths are fy = 60 ksi and f = 6000 psi. The Young's modulus of steel is 29000 ksi. (a) Fill in the blanks in the interaction diagram shown below. 30" Ast 6 No. 10 bars = Pn (1) Po (4) e = e small Load path for given e failure range Radial lines show constant (2) eb (3) e large failure range Mn (5) e= Mo (b) Compute the balanced failure point, i.e., P and Mb. H 3" P 22" I e H 3"arrow_forward
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