Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
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Chapter 17, Problem 29P
(a)
To determine
The load in the ropes.
(b)
To determine
The factor of safety for static load.
The factor of safety for static with bending.
The factor of safety for fatigue without bending.
The factor of safety for fatigue with bending.
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Chapter 17 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 17 - Example 17-2 resulted in selection of a 10-in-wide...Ch. 17 - A 6-in-widc polyamide F-l flat belt is used to...Ch. 17 - Prob. 3PCh. 17 - A flat-belt drive is to consist of two...Ch. 17 - In solving problems and examining examples, you...Ch. 17 - Return to Ex. 17-1 and complete the following. (a)...Ch. 17 - Prob. 7PCh. 17 - Prob. 8PCh. 17 - Prob. 9PCh. 17 - Two shafts 20 ft apart, with axes in the same...
Ch. 17 - Prob. 11PCh. 17 - Prob. 12PCh. 17 - A designer has to select a metal-belt drive to...Ch. 17 - Prob. 14PCh. 17 - Prob. 15PCh. 17 - Prob. 16PCh. 17 - Prob. 17PCh. 17 - Two B85 V belts are used in a drive composed of a...Ch. 17 - Prob. 19PCh. 17 - Prob. 20PCh. 17 - The geometric implications of a V-flat drive are...Ch. 17 - A 2-hp electric motor running at 1720 rev/min is...Ch. 17 - The standard roller-chain number indicates the...Ch. 17 - Prob. 24PCh. 17 - A double-strand no. 60 roller chain is used to...Ch. 17 - A four-strand no. 40 roller chain transmits power...Ch. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Prob. 33PCh. 17 - For Prob. 17-29 estimate the elongation of the...
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- Can you answer this question?arrow_forwardA gear has a gear wheel with 16 teeth. The gear should be dimensioned for the highest and lowest gear ratio. Looking for output power, torque, speed?nin= 2000 rpmmin = 30Nmn=0,9a max= 450 mmModule 4Gear limitsz1 z213 13-1614 14-2615 15-4516 16-10117 17-131418 18-…..I have calculate but I can’t get the right answers…..√16 =459x60/56x57=1.1 lowest59x60/13x13=20,94 highestnut=2000/1.1= 1818rpmnut=2000/20.94=95.5 rpmMut=1.1x30=33 NmMut=20.94x30=628,2 Nm(Right answer)LowestZ=13, M=24,4Nm, n=2462 rpmHighestZ=92, M=172,5Nm, n=347,8 rpmP=5655W on botharrow_forwardPlease see attached pic.arrow_forward
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