BIO Base pairing in DNA, I. The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the geometric shape of these molecules, adenine bonds with thymine and cytosine bonds with guanine. Figure 17.46 shows the thymine-adenine bond. Each charge shown is ±e. and the H—N distance is 0.110 nm. (a) Calculate the net force that thymine exerts on adenine. Is it attractive or repulsive? To keep the calculations fairly simple, yet reasonable, consider only the forces due to the O—H—N and the N —H—N combinations, assuming that these two combinations are parallel to each other. Remember, however, that in the O—H—N set. the O − exerts a force on both the H + and the N − , and likewise along the N—H—N set. (b) Calculate the force on the electron in the hydrogen atom, which is 0.0529 nm from the proton. Then compare the strength of the bonding force of the electron in hydrogen with the bonding force of the adenine-thymine molecules. Figure 17.46 Problem 24.
BIO Base pairing in DNA, I. The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the geometric shape of these molecules, adenine bonds with thymine and cytosine bonds with guanine. Figure 17.46 shows the thymine-adenine bond. Each charge shown is ±e. and the H—N distance is 0.110 nm. (a) Calculate the net force that thymine exerts on adenine. Is it attractive or repulsive? To keep the calculations fairly simple, yet reasonable, consider only the forces due to the O—H—N and the N —H—N combinations, assuming that these two combinations are parallel to each other. Remember, however, that in the O—H—N set. the O − exerts a force on both the H + and the N − , and likewise along the N—H—N set. (b) Calculate the force on the electron in the hydrogen atom, which is 0.0529 nm from the proton. Then compare the strength of the bonding force of the electron in hydrogen with the bonding force of the adenine-thymine molecules. Figure 17.46 Problem 24.
BIO Base pairing in DNA, I. The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the geometric shape of these molecules, adenine bonds with thymine and cytosine bonds with guanine. Figure 17.46 shows the thymine-adenine bond. Each charge shown is ±e. and the H—N distance is 0.110 nm. (a) Calculate the net force that thymine exerts on adenine. Is it attractive or repulsive? To keep the calculations fairly simple, yet reasonable, consider only the forces due to the O—H—N and the N —H—N combinations, assuming that these two combinations are parallel to each other. Remember, however, that in the O—H—N set. the O−exerts a force on both the H+ and the N−, and likewise along the N—H—N set. (b) Calculate the force on the electron in the hydrogen atom, which is 0.0529 nm from the proton. Then compare the strength of the bonding force of the electron in hydrogen with the bonding force of the adenine-thymine molecules.
Three point-like charges in the attached image are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 38.0 cm, and the point (C) is located half way between q1 and q3 along the side. Find the magnitude of the electric field at point (C). Let q1 = −2.80 µC, q2 = −3.40 µC, and q3 = −4.50 µC. Thank you.
Three point-like charges are placed as shown in the attach image, where r1 = r2 = 44.0 cm. Find the magnitude of the electric force exerted on the charge q3. Let q1 = -1.90 uC, q2 = -2.60 uC, and q3 = +3.60 uC. Thank you.
The drawing attached shows an edge-on view of two planar surfaces that intersect and are mutually perpendicular. Surface (1) has an area of 1.90 m², while Surface (2) has an area of 3.90 m². The electric field in magnitude of 215 N/C. Find the magnitude of the electric flux through surface (1 and 2 combined) if the angle theta made between the electric field with surface (2) is 30.0 degrees. Thank you.
Campbell Essential Biology with Physiology (5th Edition)
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