Excursions in Modern Mathematics, Books a la carte edition (9th Edition)
Excursions in Modern Mathematics, Books a la carte edition (9th Edition)
9th Edition
ISBN: 9780134469041
Author: Peter Tannenbaum
Publisher: PEARSON
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Chapter 17, Problem 1E

Consider the normal distribution represented by the normal curve in Fig 17-12. Assume that P is a point of inflection of the curve.

Chapter 17, Problem 1E, Consider the normal distribution represented by the normal curve in Fig 17-12. Assume that P is a

Figure 17-12

a. Find the mean μ of the distribution.

b. Find the median M of the distribution.

c. Find the standard deviation σ of the distribution.

Expert Solution
Check Mark
To determine

(a)

To find:

The mean μ of the distribution.

Answer to Problem 1E

Solution:

The mean μ of the distribution is 80lb.

Explanation of Solution

Given:

The normal distribution curve is,

Excursions in Modern Mathematics, Books a la carte edition (9th Edition), Chapter 17, Problem 1E , additional homework tip  1

With P as a point of inflection of the curve.

Definition:

The point of intersection of the horizontal (data) axis and the line of symmetry of the normal curve, the center of the distribution. The center corresponds to both the median and mean of the distribution.

Calculation:

From the given figure, it is seen that the point of intersection of the horizontal axis and the line of symmetry is at 80lb.

This implies that the mean μ of the distribution is μ=80lb.

Conclusion:

The mean μ of the distribution is 80lb.

Expert Solution
Check Mark
To determine

(b)

To find:

The median M of the distribution.

Answer to Problem 1E

Solution:

The median M of the distribution is 80lb.

Explanation of Solution

Given:

The normal distribution curve is,

Excursions in Modern Mathematics, Books a la carte edition (9th Edition), Chapter 17, Problem 1E , additional homework tip  2

With P as a point of inflection of the curve.

Definition:

The point of intersection of the horizontal (data) axis and the line of symmetry of the normal curve, the center of the distribution. The center corresponds to both the median and mean of the distribution.

Calculation:

From the given figure, it is seen that the point of intersection of the horizontal axis and the line of symmetry is at 80lb.

This implies that the median M of the distribution.is 80lb.

Conclusion:

The median M of the distribution is 80lb.

Expert Solution
Check Mark
To determine

(c)

To find:

The standard deviation σ of the distribution.

Answer to Problem 1E

Solution:

The standard deviation σ of the distribution is 10lb.

Explanation of Solution

Given:

The normal distribution curve is,

Excursions in Modern Mathematics, Books a la carte edition (9th Edition), Chapter 17, Problem 1E , additional homework tip  3

With P as a point of inflection of the curve.

Definition:

The standard deviation of the normal distribution is the horizontal distance between the axis of symmetry of the curve and one of the two points of inflection.

Calculation:

From the given figure, it is seen that the point of intersection of the horizontal axis and the line of symmetry is at 80lb.

The point of inflection of the curve is 90lb.

Therefore the distance between the point of inflection and the line of symmetry is,

9080=10lb.

This implies that the standard deviation σ of the distribution.is 10lb.

Conclusion:

The standard deviation σ of the distribution.is 10lb.

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Chapter 17 Solutions

Excursions in Modern Mathematics, Books a la carte edition (9th Edition)

Ch. 17 - Explain why a distribution with median M=82, mean...Ch. 17 - Explain why a distribution with median M=453, mean...Ch. 17 - Explain why a distribution with =195, Q1=180 and...Ch. 17 - Explain why a distribution with M==47, Q1=35 and...Ch. 17 - A normal distribution has mean =30kg and standard...Ch. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 18ECh. 17 - Prob. 19ECh. 17 - In a normal distribution with mean =83.2 and...Ch. 17 - Prob. 21ECh. 17 - Prob. 22ECh. 17 - Prob. 23ECh. 17 - Prob. 24ECh. 17 - Prob. 25ECh. 17 - In a normal distribution with standard deviation...Ch. 17 - Prob. 27ECh. 17 - Prob. 28ECh. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution defined by Fig....Ch. 17 - Consider the normal distribution defined by Fig....Ch. 17 - A normal distribution has mean =71.5in., and the...Ch. 17 - A normal distribution has standard deviation =12.3...Ch. 17 - Prob. 35ECh. 17 - Prob. 36ECh. 17 - Prob. 37ECh. 17 - A normal distribution has mean =500 and standard...Ch. 17 - In a normal distribution, what percent of the data...Ch. 17 - In a normal distribution, what percent of the data...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - An honest coin is tossed n=3600 times. Let the...Ch. 17 - Prob. 58ECh. 17 - Suppose that a random sample of n=7056 adults is...Ch. 17 - An honest die is rolled. If the roll comes out...Ch. 17 - A dishonest coin with probability of heads p=0.4...Ch. 17 - A dishonest coin with probability of heads p=0.75...Ch. 17 - Prob. 63ECh. 17 - Suppose that 1 out of every 10 plasma televisions...Ch. 17 - Prob. 65ECh. 17 - Prob. 66ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 68ECh. 17 - Prob. 69ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 71ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 73ECh. 17 - Prob. 74ECh. 17 - Prob. 75ECh. 17 - Prob. 76ECh. 17 - A dishonest coin with probability of heads p=0.1...Ch. 17 - Prob. 78ECh. 17 - In American roulette there are 18 red numbers, 18...Ch. 17 - After polling a random sample of 800 voters during...
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