(a) Explanation Section 1: To determine: The expression for t in terms of γ . Answer: The expression for t in terms of γ is t = − 1 γ . Given Info: Pressure at the triple point is 4.80 × 10 4 Pa and at boiling point is 6.50 × 10 4 Pa . Formula to calculate pressure is, P = P o ( 1 + γ t ) I P is pressure at t ° C . P o is pressure at 0 ° C . γ is pressure coefficient. t is temperature. Above equation can be written for different temperatures and pressures. P 1 = P o ( 1 + γ t 1 ) II t 1 is initial temperature. P 1 is pressure at temperature t 1 . P 2 = P o ( 1 + γ t 2 ) III t 2 is final temperature. P 2 is pressure at temperature t 2 . Equate equation II and III to find γ . γ = P 2 − P 1 P 1 t 2 − P 2 t 1 IV Substitute 0 for P in equation I to find t 0 = P o ( 1 + γ t ) 0 = ( 1 + γ t ) γ t = − 1 t = − 1 γ Section 2: To determine: The temperature in Celsius at which the gas pressure becomes zero. Answer: The temperature in Celsius at which the gas pressure becomes zero is − 282 ° C (b) To determine The gas in the thermometer obeys expression T 1 T 2 = P 1 P 2 or not and also the pressure that the experimenter had measured at 0.01 ° C .

University Physics with Modern Physics, Books a la Carte Plus Mastering Physics with eText -- Access Card Package (14th Edition)

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ISBN: 9780133983623

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Chapter 17, Problem 17.9E

(a)

To determine

The expression for t in terms of γ and temperature in Celsius at which the gas pressure becomes zero.

(b)

To determine

The gas in the thermometer obeys expression T1T2=P1P2 or not and also the pressure that the experimenter had measured at 0.01°C .

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Chapter 17, Problem 17.8E

Chapter 17, Problem 17.10E

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University Physics with Modern Physics, Books a la Carte Plus Mastering Physics with eText -- Access Card Package (14th Edition)

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The expression for t in terms of γ and temperature in Celsius at which the gas pressure becomes zero.

Solution Summary: The author explains the expression for t in terms of gamma and temperature in Celsius at which the gas pressure becomes zero.

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The expression for t in terms of γ and temperature in Celsius at which the gas pressure becomes zero.

The gas in the thermometer obeys expression T1T2=P1P2 or not and also the pressure that the experimenter had measured at 0.01°C .

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Chapter 17 Solutions