Chapter 17, Problem 17.38P

Interpretation Introduction

Interpretation:

For the reaction, ${\text{CO}}_{\text{(g)}}{\text{ + H}}_{\text{2}}{\text{O}}_{\text{(g)}}\stackrel{}{\rightleftharpoons }{\text{ CO}}_{\text{2(g)}}{\text{ + H}}_{\text{2(g)}}$ and the given reaction condition, the direction to which the reaction will proceed has to be given.

Concept Introduction:

Relation between ${\text{K}}_{\text{p}}$ and ${\text{K}}_{\text{c}}$:

The relation between and ${\text{K}}_{\text{p}}$ and ${\text{K}}_{\text{c}}$ is given by the following equation.

  ${\text{K}}_{\text{p}}{\text{ = K}}_{\text{c}}{\text{(RT)}}^{\Delta \text{ngas}}$

Where,

${\text{K}}_{\text{p}}$ is the equilibrium constant in terms of partial pressure

${\text{K}}_{\text{c}}$ is the equilibrium constant in terms of concentration

$\Delta \text{ngas = moles of gaseous product - moles of gaseous reactant}$

Comparison of ${\text{Q}}_{\text{c}}{\text{ and K}}_{\text{c}}$ :

When ${\text{Q}}_{\text{c}}{\text{ < K}}_{\text{c}}$, the reaction will proceed in right direction, $\text{reactants}\stackrel{}{\to }\text{products}$

When ${\text{Q}}_{\text{c}}{\text{ > K}}_{\text{c}}$, the reaction will proceed in left direction, $\text{reactants}\stackrel{}{\leftarrow }\text{products}$

When ${\text{Q}}_{\text{c}}{\text{ = K}}_{\text{c}}$, the reaction will remain unchanged, $\text{reactants}\stackrel{}{\rightleftharpoons }\text{products}$