PRINCIPLES OF GEOTECH.ENGINEERING >LL+M
PRINCIPLES OF GEOTECH.ENGINEERING >LL+M
9th Edition
ISBN: 9781337583879
Author: Das
Publisher: CENGAGE L
Question
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Chapter 17, Problem 17.1P
To determine

Find the area ratio for each case and appropriate sample for the given soil characterization tests.

Expert Solution & Answer
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Answer to Problem 17.1P

The area ratio for tube 1 is 5.06%_.

The area ratio for tube 2 is 4.47%_.

The area ratio for tube 3 is 4.98%_.

Explanation of Solution

Given information:

The outside diameter (Do) for sample 1 is 50.8mm.

The outside diameter (Do) for sample 2 is 76.2mm.

The outside diameter (Do) for sample 3 is 127mm.

The wall thickness (t) for sample 1 is 1.24mm.

The wall thickness (t) for sample 2 is 1.65mm.

The wall thickness (t) for sample 3 is 3.05mm.

Calculation:

Calculate the inside diameter (Di) for tube 1 using the relation as follows:

(Di)=Dot (1)

Substitute 50.8mm for (Do) and 1.24mm for t in Equation (1).

(Di)=50.81.24=49.56mm

Find the area ratio for (Ar) tube 1 using the Equation as follows:

Ar(%)=Do2Di2Di2×100 (2)

Here, Di inside diameter of sample 1.

Substitute 50.8mm for Do and 49.56mm for Di in Equation (2).

Ar(%)=50.8249.56249.562×100=2,580.642,456.192,456.19×100=124.442,456.19×100=5.06%10%

Thus, the area ratio for tube 1 is 5.06%_.

Calculate the inside diameter (Di) for tube 2 using the relation as follows:

Substitute 76.2mm for (Do) and 1.65mm for t in Equation (1).

(Di)=76.21.65=74.55mm

Find the area ratio for (Ar) tube 2 using the Equation as follows:

Substitute 76.2mm for Do and 74.55mm for Di in Equation (2).

Ar(%)=76.2274.55274.552×100=5,806.445,557.75,557.7×100=248.745,557.7×100=4.47%10%

Thus, the area ratio for tube 2 is 4.47%_.

Calculate the inside diameter (Di) for tube 3 using the relation as follows:

Substitute 127mm for (Do) and 3.05mm for t in Equation (1).

(Di)=1273.05=123.95mm

Find the area ratio for (Ar) tube 3 using the Equation as follows:

Substitute 127mm for Do and 123.95mm for Di in Equation (2).

Ar(%)=1272123.952123.952×100=16,12915,363.6015,363.60×100=4.98%10%

Thus, the area ratio for tube 3 is 4.98%_.

A soil sample usually can be considered undisturbed if the area ratio is less than or equal to 10%.

  • All the given three samples are considered as undisturbed sample, hence, it is suitable for consolidation and unconfined compression test.
  • The Grain size distribution, atterberg limits are conducted only when the soil on remolded or disturbed soil, hence, sample disturbance is not a factor.

Thus, the all three samples are appropriate for all tests.

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