Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 17, Problem 17.13P
To determine
Find the elastic settlement of the foundation using the strain influence factor method.
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11.1
A vertical column load, P = 600 kN, is applied to a rigid concrete foundation
with dimensions B = 1 m and L = 2 m, as shown in Figure 11.45. The founda-
tion rests at a depth D₁ = 0.75 m on a uniform dense sand with the following
properties: average modulus of elasticity, E¸ 20,600 kN/m², and Poisson's
ratio, μ = 0.3. Estimate the elastic settlement due to the net applied pressure,
Ao, on the foundation. Given: H = 5 m.
Foundation
BXL
Figure 11.45
600 KN
V
74
Ao
Soil
Ms = 0.3
Es = 20, 600 kN/m²
Rock
=
0.75 m
5.0 m
Q. 12
A soil profile at a certain location is as shown in figure. A rigid circular foundation of 4 m diameter rests on the sand. The contact pressure at the underside of the foundation is 230 kN/m?. The average coefficient of compressibility of the clay is 0.65 × 10-3 m2/kN for the stress range encountered. The ultimate settlement of the foundation assuming 45° load distribution
A soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at an additional stress of 160 kN/m2. Determine the cohesion of soil Hint: Draw the Mohr Circle.
a.45.5
b.19
c.43
d.54.5
Chapter 17 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
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- A soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at an additional stress of 160 kN/m2. Determine angle of friction Hint: Draw the Mohr Circle a.19 b.45.5 c.43 d.54.5arrow_forwardExercise 4.2 The plan of a foundation is given in Fig. 1. The uniform pressure on the soil is 40 kPa. Determine the vertical stress increment due to the foundation at a depth of 5 m below the point X 3 m 3 m 3 m 2 m 1.5 m 2 m 0.5 mt soil mechanicsarrow_forwardFrom the given soil formation of the soil with the following properties is shown in the figure. (see picture below) Compute the total stress at the mid-layer of the clay. (Answer: 260.745 kPa) Compute the effective stress at the mid layer of the clay. (Answer: 147.93 kPa) If a load of 1800 kN is acting on the footing 2m x 2m is placed on the ground, find the stress increase at the mid layer of the clay assuming a stress distribution of 1 horizontal to 2 vertical. (Answer: 11.64 kPa) *unit weight of dry sand = 14.72 kN/m3*arrow_forward
- The vertical and horizontal stresses at a certain point in soil are as follows:σx = 50 kPaσx = 100 kPaτzx = - 20 kPa a) Determine magnitudes and directions of the major and minor principal stresses.b) Determine magnitude and direction of maximum shear stress.c) Determine the normal and shear stresses acting on a soil element inclined at 60 clockwise from the horizontal plane.arrow_forwardA soil has an angle of shearing of 30° and cohesion of 35 kN/m^2. If the specimen of this soil is subjected to a tri-axial compression test, then the value of lateral pressure in the cell for failure to occur at total stress of 300 kN/m² will be (a) 243.21 kN/m2 (c) 103.21kN /(m2) (b) 44.41 kN/m² (d) 59.59kN/(m2)arrow_forwardDetermine the increase in vertical stress at a depth of 5 m below the centroid of the foundation shown in Figure 2.arrow_forward
- From the given soil formation of the soil with the following properties is shown in the figure. (see picture below) Compute the total stress at the mid-layer of the clay. (Answer: ) Compute the effective stress at the mid layer of the clay. If a load of 1800 kN is acting on the footing 2m x 2m is placed on the ground, find the stress increase at the mid layer of the clay assuming a stress distribution of 1 horizontal to 2 vertical. *unit weight of dry sand = 14.72 kN/m3*arrow_forwardPlease solve step by step clearlyarrow_forwardAnother method of determining the capillary rise in a soil is to use Hazen's capillary formula. The 3 m thick dense silt layer shown below is the top stratum of a construction site, has an effective diameter of 0.01 mm. What is the approximate height of the capillary rise in that silt stratum? What are the vertical effective stresses at depths of 3 m and 8 m below the surface? The "free ground water" level is 8 meters below the ground surface, the y's=26.5 kN/m³, and the soil between the ground surface and the capillary level is partially saturated to 50%. Dense silt Clay h₁ = 3 m h₂=5 marrow_forward
- A soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at an additional stress of 160 kN/m2. Determine angle of friction. Draw the Mohr Circlearrow_forwardA cylindrical sample of saturated clay 4 cm in diameter and 8 cm high was tested in an unconfined compression apparatus. Find the unconfined compression strength, if the specimen failed at an axial load of 360 N, when the axial deformation was 8 mm. Find the cohesion in kPa if the angle made by the failure plane with the horizontal plane was recorded as 50°. Include free body diagram. a.312 b.106 c.258 d.210arrow_forwardA soil has an unconfined compressive strength of 120 kN/m2. In a triaxial compression test, a specimen of the same soil when subjected to a chamber pressure of 40 kN/m2 failed at additional stress of 160 kN/m2. Determine the angle made by the failure plane with the axial stress in the triaxial test. Hint: Draw the Mohr Circle. a.19 b.54.5 c.45.5 d.43arrow_forward
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