An analytical chemist has a solution containing chloride ion, Cl − . She decides to determine the amount of chloride ion in the solution by titrating 50.0 mL of this solution by 0.100 M AgNO 3 . As a way to indicate the endpoint of the titration, she added 1.00 g of potassium chromate, K 2 CrO 4 (see Figure 17.5). As she slowly added the silver nitrate to the solution, a white precipitate formed. She continued the titration, with more white precipitate forming. Finally, the solution turned red, from another precipitate. The volume of the solution at this point was 60.3 mL. How many moles of chloride ion were there in the original solution? How many moles of chloride ion were there in the final solution? You may make any reasonable approximations.
An analytical chemist has a solution containing chloride ion, Cl − . She decides to determine the amount of chloride ion in the solution by titrating 50.0 mL of this solution by 0.100 M AgNO 3 . As a way to indicate the endpoint of the titration, she added 1.00 g of potassium chromate, K 2 CrO 4 (see Figure 17.5). As she slowly added the silver nitrate to the solution, a white precipitate formed. She continued the titration, with more white precipitate forming. Finally, the solution turned red, from another precipitate. The volume of the solution at this point was 60.3 mL. How many moles of chloride ion were there in the original solution? How many moles of chloride ion were there in the final solution? You may make any reasonable approximations.
An analytical chemist has a solution containing chloride ion, Cl−. She decides to determine the amount of chloride ion in the solution by titrating 50.0 mL of this solution by 0.100 M AgNO3. As a way to indicate the endpoint of the titration, she added 1.00 g of potassium chromate, K2CrO4 (see Figure 17.5). As she slowly added the silver nitrate to the solution, a white precipitate formed. She continued the titration, with more white precipitate forming. Finally, the solution turned red, from another precipitate. The volume of the solution at this point was 60.3 mL. How many moles of chloride ion were there in the original solution? How many moles of chloride ion were there in the final solution? You may make any reasonable approximations.
Part 3: AHm,system
Mass of 1.00 M HCI
Vol. of 1.00 M HCI
Mass of NaOH(s)
Total Mass in Calorimeter
Mole product if
HCI limiting reactant
Trial 1
62.4009
1.511g
Mole product if
NaOH limiting reactant
Limiting reactant
Initial Temperature
Final Temperature
23.8°C
37.6°C
Change in Temperature
AHm,system (calculated)
Average AHm,system
(calculated)
(calculated)
(calculated)
Trial 2
64.006g
1.9599
(calculated)
(calculated)
(calculated)
(calculated)
(calculated)
(calculated)
24.7°C
41.9°C
(calculated)
(calculated)
(2 pts. each)
Don't used Ai solution
What is the numerical value of the slope
using the equation y=-1.823x -0.0162
please show calculations
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell