Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card
Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card
10th Edition
ISBN: 9781337129039
Author: Frederick J Gravetter, Larry B. Wallnau
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 17, Problem 13P

  1. In a classic study, Loftus and Palmer (1974) investigated the relationship between memory for eyewitnesses and the question they are asked.

In the study participants watched a film of an automobile accident and then were questioned about the accident. One group was asked how fast the cars were going when they “smashed into” each other.

A second group was asked about the speed when the cars “hit” each other, and a third group was not asked any question about the speed of the cars. A week later, the participants returned to answer additional questions about the accident, including whether they recalled. Seeing any broken glass. Although there was no broken glass in the film, several students claimed to remember seeing it. The following table shows the frequency distribution of response for each group.

Response to the Question

Did You See Any Broken Glass?

Verb Used to Ask About the Speed

Verb Used as Ask About the Speed

Smashed into Hit

Control (Not Asked)

Response About Broken Glass

Yes  No

  1. Does the proportion of participants who claim to remember broken glass differ significantly from group to group? Test with a = .05.
  2. Compute Cramer’s V to measure the size of the
  3. treatment effect.

  • Describe how the phrasing of the question influenced
  • the participants’ memories.

  • Write a sentence demonstrating how the outcome of the hypothesis test and the p1easure of effect size would be reported in a journal article.
  • Expert Solution & Answer
    Check Mark
    To determine

    The relationship between memory for eyewitness and the questions they were asked.

    Answer to Problem 13P

    Solution:

    a) The test statistic of 7.778 is greater that the critical value of 5.991, hence, we reject the null hypothesis.

    b) The Cramer's V obtained is 0.228.

    c) The influence of the phrasing of the question on the participant's memeories is explained

    d) A sentence demonstrating the outcome of the hypothesis test and the measure of effect size to be reported in a journal article is provided.

    Explanation of Solution

    a) Null Hypothesis H0: The memory for eyewitness and the question they were asked is independent. Alternate Hypothesis Ha: The memory for eyewitness and the question they asked is not independent.

    Using the χ 2 -test for independence.

    The test statistic is

    χ 2 = i=1 n ( O i E i ) 2 E i Where, O i : observed frequency, E i : expected frequency, Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card, Chapter 17, Problem 13P , additional homework tip  1number of cells

    The expected frequencies are calculated as

    E i = R×C Total Where, Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card, Chapter 17, Problem 13P , additional homework tip  2& Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card, Chapter 17, Problem 13P , additional homework tip  3are the Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card, Chapter 17, Problem 13P , additional homework tip  4cell's corresponding row & column total.

    Response To Broken Glass Total
    Yes No
    Smashed Into O 1 =16 O 2 =34 50 E 1 =9.67 E 2 =40.33
    Hit O 3 =7 O 4 =43 50 E 3 =9.67 E 4 =40.33
    Control (Not asked) O 5 =6 O 6 =44 50 E 5 =9.67 E 6 =40.33
    Total 29 121 150

    The observed value of the test statistic is:

    χ obs 2 = i=1 6 ( O i E i ) 2 E i =7.778

    The critical value from the χ 2 -table is χ 0.05;(31)(21) 2 = χ 0.05;2 2 =5.991 .

    b) Cramer's V is calculated as

    V= χ obs 2 /Total min(k1,r1) , where Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card, Chapter 17, Problem 13P , additional homework tip  5& Bundle: Statistics for the Behavioral Sciences, Loose-leaf Version, 10th + Aplia, 1 term Printed Access Card, Chapter 17, Problem 13P , additional homework tip  6are the number of columns and rows respectively.

    V= 7.778/150 1 =0.228

    c) The phrasing of the question has a significant influence on the memory of the eyewitness. We can see this from both the Chi square test and Cramer's V that there is a moderately strong association between the eyewitness and the questions asked, and the way the question is phrased might change the way an eyewitness answers it.

    d) From the result of the hypothesis testing, we can see that there is a significant relationship between the eyewitness and the question they were asked. We know this as the the test satstistic is greater than the critical value allowing us to reject null hypothesis. The measure of the relationship can be obtained from the result of the Cramer's V. We can also see from the Cramer's V of 0.228, that the association between the variables is moderately strong (0.20-0.25).

    Conclusion:

    We conclude that the memory for eyewitness and the question they were asked are dependent, i.e. the proportion of participants who claim to remember broken glass differ significantly from group to group at 5% level of significance.

    Justification:

    As the observed value of the test statistic is greater than the critical value, we reject H 0 at 5% level of significance.

    Want to see more full solutions like this?

    Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
    Knowledge Booster
    Background pattern image
    Statistics
    Learn more about
    Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
    Recommended textbooks for you
    Text book image
    Glencoe Algebra 1, Student Edition, 9780079039897...
    Algebra
    ISBN:9780079039897
    Author:Carter
    Publisher:McGraw Hill
    Text book image
    Functions and Change: A Modeling Approach to Coll...
    Algebra
    ISBN:9781337111348
    Author:Bruce Crauder, Benny Evans, Alan Noell
    Publisher:Cengage Learning
    Text book image
    Big Ideas Math A Bridge To Success Algebra 1: Stu...
    Algebra
    ISBN:9781680331141
    Author:HOUGHTON MIFFLIN HARCOURT
    Publisher:Houghton Mifflin Harcourt
    Text book image
    Holt Mcdougal Larson Pre-algebra: Student Edition...
    Algebra
    ISBN:9780547587776
    Author:HOLT MCDOUGAL
    Publisher:HOLT MCDOUGAL
    Statistics 4.1 Point Estimators; Author: Dr. Jack L. Jackson II;https://www.youtube.com/watch?v=2MrI0J8XCEE;License: Standard YouTube License, CC-BY
    Statistics 101: Point Estimators; Author: Brandon Foltz;https://www.youtube.com/watch?v=4v41z3HwLaM;License: Standard YouTube License, CC-BY
    Central limit theorem; Author: 365 Data Science;https://www.youtube.com/watch?v=b5xQmk9veZ4;License: Standard YouTube License, CC-BY
    Point Estimate Definition & Example; Author: Prof. Essa;https://www.youtube.com/watch?v=OTVwtvQmSn0;License: Standard Youtube License
    Point Estimation; Author: Vamsidhar Ambatipudi;https://www.youtube.com/watch?v=flqhlM2bZWc;License: Standard Youtube License