ORGANIC CHEMISTRYPKGDRL+MLCRL MDL
ORGANIC CHEMISTRYPKGDRL+MLCRL MDL
3rd Edition
ISBN: 9781119416746
Author: Klein
Publisher: WILEY
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Chapter 16.8, Problem 19CC
Interpretation Introduction

Interpretation:

The given [4+4] cycloaddition process should be explained with the use of MO theory whether it occurs through thermal or photochemical pathway.

Concept introduction:

According to MO theory,

  • In a molecule, the atomic orbitals of atoms constituted in the molecule are combined to produce new orbitals are called Molecular Orbitals.
  • The numbers of MO’s are equals to the number of atomic orbitals are combined in such a way that the linear combination of similar atomic orbitals to form equal numbers of bonding and anti-bonding MO’s.
  • The bonding MO’s are lower in energy than the anti-bonding MO’s.
  • HOMO is the highest energized occupied orbital in the MO’s.
  • LUMO is the lowest energized orbital in the MO’s.

Frontier orbital theory says,

  • In a cycloaddition reaction, the electron cloud flows from HOMO of the one molecule to LUMO of the other molecule.

According to conservation of orbital symmetry,

  • The phases of MO’s (HOMO & LUMO) of reactants must be symmetric in order to reaction occur.
  • The thermal pathway of cycloaddition reaction occurs in the ground state of 1,3-butadiene.
  • The photochemical pathway of cycloaddition reaction occurs in the excited state of 1,3-butadiene.

To explain: the given [4+4] cycloaddition process with the use of MO theory whether it occurs through thermal or photochemical pathway.

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Chapter 16 Solutions

ORGANIC CHEMISTRYPKGDRL+MLCRL MDL

Ch. 16.5 - Prob. 9PTSCh. 16.5 - Prob. 10PTSCh. 16.5 - Prob. 11ATSCh. 16.5 - Prob. 12CCCh. 16.7 - Prob. 3LTSCh. 16.7 - Prob. 13PTSCh. 16.7 - Prob. 14ATSCh. 16.7 - Prob. 15CCCh. 16.7 - Prob. 16CCCh. 16.7 - Prob. 17CCCh. 16.7 - Predict the regiochemical outcome (major product)...Ch. 16.8 - Prob. 19CCCh. 16.9 - Prob. 20CCCh. 16.9 - Prob. 4LTSCh. 16.9 - Prob. 21PTSCh. 16.9 - Prob. 22ATSCh. 16.10 - Prob. 23CCCh. 16.10 - Prob. 24CCCh. 16.10 - Prob. 25CCCh. 16.10 - Prob. 26CCCh. 16.11 - Prob. 5LTSCh. 16.11 - Prob. 27PTSCh. 16.11 - Prob. 28ATSCh. 16.12 - Prob. 29CCCh. 16 - Prob. 30PPCh. 16 - Prob. 31PPCh. 16 - Prob. 32PPCh. 16 - Prob. 33PPCh. 16 - Prob. 34PPCh. 16 - Prob. 35PPCh. 16 - Prob. 36PPCh. 16 - Prob. 37PPCh. 16 - Prob. 38PPCh. 16 - Prob. 39PPCh. 16 - Prob. 40PPCh. 16 - Prob. 41PPCh. 16 - Prob. 42PPCh. 16 - Prob. 43PPCh. 16 - Prob. 44PPCh. 16 - Prob. 45PPCh. 16 - Prob. 46PPCh. 16 - Prob. 47PPCh. 16 - Prob. 48PPCh. 16 - Prob. 49PPCh. 16 - Prob. 50PPCh. 16 - Prob. 51PPCh. 16 - Prob. 52PPCh. 16 - Prob. 53PPCh. 16 - Prob. 54PPCh. 16 - Prob. 55PPCh. 16 - Prob. 56PPCh. 16 - Prob. 57PPCh. 16 - Prob. 58PPCh. 16 - Prob. 59PPCh. 16 - Prob. 60IPCh. 16 - Prob. 61IPCh. 16 - Prob. 62IPCh. 16 - Prob. 63IPCh. 16 - Prob. 64IPCh. 16 - Prob. 65IPCh. 16 - Prob. 66IPCh. 16 - Prob. 67IPCh. 16 - Prob. 68IPCh. 16 - Prob. 69IPCh. 16 - Prob. 70IPCh. 16 - Prob. 71IPCh. 16 - Prob. 72IPCh. 16 - Prob. 73IPCh. 16 - Prob. 74IPCh. 16 - Prob. 76IPCh. 16 - Prob. 77CPCh. 16 - Prob. 78CPCh. 16 - Prob. 79CPCh. 16 - Prob. 80CPCh. 16 - Prob. 81CP
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