Chapter 16.5, Problem 3PS

To determine

To find: The length of the side AF.

Answer to Problem 3PS

The length of the side AFis $10\text{units}$ .

Explanation of Solution

Given information:

The triangle $\Delta \text{ABC}$ is given.

Assign the ratios and the weights as shown below,

  

The length of the side AFis calculated as,

  $\begin{array}{l}{w}_1\left(BF\right)=w_2\left(AF\right)\\ \left(\frac{1}{2}\right)\left(20\right)=\left(1\right)AF\\ AF=10\text{unit}\end{array}$

Thus, the length of the side AF is $10\text{units}$ .