Explanation Use parametrization of the cone to determine the surface area. Given : The equation of the cone x 2 + y 2 = z 2 Formula used : Area () = ∬ D ‖ n ‖ d u d v Calculation The surface area of the cone can be parametrized as φ ( u , v ) = ( u cos v , u sin v , u ) The normal vector is given by n = 〈 −...

Loose-Leaf Version for Calculus: Early Transcendentals Single Variable

4th Edition

ISBN: 9781319312886

Author: Rogawski, Jon, Adams, Colin, FRANZOSA, Robert

Publisher: W. H. Freeman

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Question

Chapter 16.4, Problem 36E

To determine

To calculate:

The surface area of the part of the cone $x^{2} + y^{2} = z^{2}$ between the planes $z = 2$ and $z = 5$

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Chapter 16.4, Problem 35E

Chapter 16.4, Problem 37E

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Chapter 16 Solutions

Loose-Leaf Version for Calculus: Early Transcendentals Single Variable

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Knowledge Booster

The surface area of the part of the cone x 2 + y 2 = z 2 between the planes z = 2 and z = 5

To calculate: The surface area of the part of the cone x2+y2=z2 between the planes z = 2 and z = 5

Want to see the full answer?

Chapter 16 Solutions

To calculate:

The surface area of the part of the cone $x^{2} + y^{2} = z^{2}$ between the planes $z = 2$ and $z = 5$