Explanation Given information: The system of equations is shown below: 2 x − y − z = 7 4 x − 3 y + 2 z = 4 3 x + 5 y + z = − 10 Calculation: The system of equations can be expressed as, [ 2 − 1 − 1 4 − 3 2 3 5 1 ] [ x y z ] = [ 7 4 − 10 ] Set up the matrices A , X , and C using the system of equations as follows: A = [ 2 − 1 − 1 4 − 3 2 3 5 1 ] X = [ x y z ] C = [ 7 4 − 10 ] The system of Equations is of the form A X = C and the solution of the equations is X = A − 1 C . The procedure to obtain the solution of system of equations ( X = A − 1 C ) using graphing calculator is explained below: Press 2 nd and x − 1 key and that move the arrow to the right end to select “EDIT” and choose the name [ A ] . Enter the dimensions of the matrix as 3 × 3 matrix and enter the elements [ 2 − 1 − 1 4 − 3 2 3 5 1 ]

11th Edition

ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Matrices

‘Matrices’ is the plural form of the word matrix, and it is basically a spreadsheet in the form of a box. In mathematics, various functions can be carried out with matrices. Generally, a matrix comes in the shape of a square or rectangle. The elements ar…

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Chapter 16.4, Problem 21E

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Find the solution of the system of equations using the coefficient matrix. Use the graphic calculator to do the necessary matrix operations.

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Chapter 16.4, Problem 20E

Chapter 16.4, Problem 22E

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| Without evaluating the Legendre symbols, prove the following. (i) 1(173)+2(2|73)+3(3|73) +...+72(72|73) = 0. (Hint: As r runs through the numbers 1,2,. (ii) 1²(1|71)+2²(2|71) +3²(3|71) +...+70² (70|71) = 71{1(1|71) + 2(2|71) ++70(70|71)}. 72, so does 73 – r.)

Chapter 16 Solutions

Basic Technical Mathematics

Ch. 16.1 - For matrices A and B, find A + B. Ch. 16.1 - Prob. 2PE Ch. 16.1 - Prob. 3PE Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E Ch. 16.1 - In Exercises 3–10, determine the value of the...Ch. 16.1 - Prob. 6E Ch. 16.1 - Prob. 7E

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