
Chemistry: The Science in Context (Fifth Edition)
5th Edition
ISBN: 9780393614046
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster, Stacey Lowery Bretz, Geoffrey Davies
Publisher: W. W. Norton & Company
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Question
Chapter 16.3, Problem 8PE
Interpretation Introduction
Interpretation: The change in
Concept introduction: The potential of
To determine: The change in
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In the electrode Pt, H2(1 atm) | H+(a=1), if the electrode balance potential is -0.118 V and the interface potential difference is +5 mV. The current voltage will be 0.005 - (-0.118) = 0.123 V ¿Correcto?
In the electrode Pt, H2(1 atm) | H+(a=1) at 298K is 0.79 mA cm-2. If the balance potential of the electrode is -0.118 V and the potential difference of the interface is +5 mV. Determine its potential.
In one electrode: Pt, H2(1 atm) | H+(a=1), the interchange current density at 298K is 0.79 mA·cm-2. If the voltage difference of the interface is +5 mV. What will be the correct intensity at pH = 2?. Maximum transfer voltage and beta = 0.5.
Chapter 16 Solutions
Chemistry: The Science in Context (Fifth Edition)
Ch. 16.2 - Prob. 1PECh. 16.2 - Prob. 2PECh. 16.3 - Prob. 3PECh. 16.3 - Prob. 4PECh. 16.3 - Prob. 5PECh. 16.3 - Prob. 6PECh. 16.3 - Prob. 7PECh. 16.3 - Prob. 8PECh. 16.4 - Prob. 9PECh. 16.4 - Prob. 10PE
Ch. 16.4 - Prob. 11PECh. 16.4 - Prob. 12PECh. 16.5 - Prob. 13PECh. 16.6 - Prob. 14PECh. 16.8 - Prob. 15PECh. 16.8 - Prob. 16PECh. 16.8 - Prob. 17PECh. 16.8 - Prob. 18PECh. 16.8 - Prob. 19PECh. 16 - Prob. 16.1VPCh. 16 - Prob. 16.2VPCh. 16 - Prob. 16.3VPCh. 16 - Prob. 16.4VPCh. 16 - Prob. 16.5VPCh. 16 - Prob. 16.6VPCh. 16 - Prob. 16.7VPCh. 16 - Prob. 16.8VPCh. 16 - Prob. 16.9VPCh. 16 - Prob. 16.10VPCh. 16 - Prob. 16.11QPCh. 16 - Prob. 16.12QPCh. 16 - Prob. 16.13QPCh. 16 - Prob. 16.14QPCh. 16 - Prob. 16.15QPCh. 16 - Prob. 16.16QPCh. 16 - Prob. 16.17QPCh. 16 - Prob. 16.18QPCh. 16 - Prob. 16.19QPCh. 16 - Prob. 16.20QPCh. 16 - Prob. 16.21QPCh. 16 - Prob. 16.22QPCh. 16 - Prob. 16.23QPCh. 16 - Prob. 16.24QPCh. 16 - Prob. 16.25QPCh. 16 - Prob. 16.26QPCh. 16 - Prob. 16.27QPCh. 16 - Prob. 16.28QPCh. 16 - Prob. 16.29QPCh. 16 - Prob. 16.30QPCh. 16 - Prob. 16.31QPCh. 16 - Prob. 16.32QPCh. 16 - Prob. 16.33QPCh. 16 - Prob. 16.34QPCh. 16 - Prob. 16.35QPCh. 16 - Prob. 16.36QPCh. 16 - Prob. 16.37QPCh. 16 - Prob. 16.38QPCh. 16 - Prob. 16.39QPCh. 16 - Prob. 16.40QPCh. 16 - Prob. 16.41QPCh. 16 - Prob. 16.42QPCh. 16 - Prob. 16.43QPCh. 16 - Prob. 16.44QPCh. 16 - Prob. 16.45QPCh. 16 - Prob. 16.46QPCh. 16 - Prob. 16.47QPCh. 16 - Prob. 16.48QPCh. 16 - Prob. 16.49QPCh. 16 - Prob. 16.50QPCh. 16 - Prob. 16.51QPCh. 16 - Prob. 16.52QPCh. 16 - Prob. 16.53QPCh. 16 - Prob. 16.54QPCh. 16 - Prob. 16.55QPCh. 16 - Prob. 16.56QPCh. 16 - Prob. 16.57QPCh. 16 - Prob. 16.58QPCh. 16 - Prob. 16.59QPCh. 16 - Prob. 16.60QPCh. 16 - Prob. 16.61QPCh. 16 - Prob. 16.62QPCh. 16 - Prob. 16.63QPCh. 16 - Prob. 16.64QPCh. 16 - Prob. 16.65QPCh. 16 - Prob. 16.66QPCh. 16 - Prob. 16.67QPCh. 16 - Prob. 16.68QPCh. 16 - Prob. 16.69QPCh. 16 - Prob. 16.70QPCh. 16 - Prob. 16.71QPCh. 16 - Prob. 16.72QPCh. 16 - Prob. 16.73QPCh. 16 - Prob. 16.74QPCh. 16 - Prob. 16.75QPCh. 16 - Prob. 16.76QPCh. 16 - Prob. 16.77QPCh. 16 - Prob. 16.78QPCh. 16 - Prob. 16.79QPCh. 16 - Prob. 16.80QPCh. 16 - Prob. 16.81QPCh. 16 - Prob. 16.82QPCh. 16 - Prob. 16.83QPCh. 16 - Prob. 16.84QPCh. 16 - Prob. 16.85QPCh. 16 - Prob. 16.86QPCh. 16 - Prob. 16.87QPCh. 16 - Prob. 16.88QPCh. 16 - Prob. 16.89QPCh. 16 - Prob. 16.90QPCh. 16 - Prob. 16.91QPCh. 16 - Prob. 16.92QPCh. 16 - Prob. 16.93QPCh. 16 - Prob. 16.94QPCh. 16 - Prob. 16.95QPCh. 16 - Prob. 16.96QPCh. 16 - Prob. 16.97QPCh. 16 - Prob. 16.98QPCh. 16 - Prob. 16.99QPCh. 16 - Prob. 16.100QPCh. 16 - Prob. 16.101QPCh. 16 - Prob. 16.102QPCh. 16 - Prob. 16.103QPCh. 16 - Prob. 16.104QPCh. 16 - Prob. 16.105QPCh. 16 - Prob. 16.106QPCh. 16 - Prob. 16.107QPCh. 16 - Prob. 16.108QPCh. 16 - Prob. 16.109QPCh. 16 - Prob. 16.110QPCh. 16 - Prob. 16.111APCh. 16 - Prob. 16.112APCh. 16 - Prob. 16.113APCh. 16 - Prob. 16.114APCh. 16 - Prob. 16.115APCh. 16 - Prob. 16.116APCh. 16 - Prob. 16.117APCh. 16 - Prob. 16.118AP
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- In a Pt electrode, H2(1 atm) | H+(a=1), the interchange current density of an electrode is 0.79 mA cm-2. ¿Qué corriente flow across the electrode of área 5 cm2 when the difference in potential of the interface is +5 mV?.arrow_forwardIf the current voltage is n = 0.14 V, indicate which of the 2 voltage formulas of the ley of Tafel must be applied i a a) == exp (1-B). xp[(1 - ß³): Fn Fn a b) == exp B RT RTarrow_forwardIf the current voltage is n = 0.14 V. Indicate which of the 2 formulas must be applied a) = a T = i exp[(1 - p) F Fn Fn b) i==exp B RTarrow_forward
- Topic: Photochemistry and Photophysics of Supramoleculesarrow_forwardTwo cations that exchange an electron in an interface, the exchange density is worth 1.39 mA/cm2 and the current density is worth 15 mA/cm2 at 25°C. If the overvoltage is 0.14 V, calculate the reaction rate and symmetry factor. Data: R = 8,314 J mol-1 k-1: F = 96500 Carrow_forwardWith the help of the Tafel line, it is estimated that the interchange density of the VO2+/VO2+ system on the carbon paper has a value of 3 mA cm-2. Calculate a) the current density if the voltage has a value of 1.6 mV and the temperature is 25°C. b) the beta value of the anódico process if the Tafel pendulum is 0.6 V at 25°C. Data: R = 8.314 JK-1mol-1, y F = 96485 C mol-1.arrow_forward
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