Improper integrals Improper integrals arise in polar coordinates when the radial coordinate r becomes arbitrarily large. Under certain conditions, these integrals are treated in the usual way: ∫ α β ∫ a ∞ f ( r , θ ) r d r d θ = lim b → ∞ ∫ α β ∫ a b f ( r , θ ) r d r d θ . Use this technique to evaluate the following integrals. 63. ∫ 0 π / 2 ∫ 1 ∞ cos θ r 3 r d r d θ
Improper integrals Improper integrals arise in polar coordinates when the radial coordinate r becomes arbitrarily large. Under certain conditions, these integrals are treated in the usual way: ∫ α β ∫ a ∞ f ( r , θ ) r d r d θ = lim b → ∞ ∫ α β ∫ a b f ( r , θ ) r d r d θ . Use this technique to evaluate the following integrals. 63. ∫ 0 π / 2 ∫ 1 ∞ cos θ r 3 r d r d θ
Improper integralsImproper integrals arise in polar coordinates when the radial coordinate r becomes arbitrarily large. Under certain conditions, these integrals are treated in the usual way:
∫
α
β
∫
a
∞
f
(
r
,
θ
)
r
d
r
d
θ
=
lim
b
→
∞
∫
α
β
∫
a
b
f
(
r
,
θ
)
r
d
r
d
θ
.
Use this technique to evaluate the following integrals.
63.
∫
0
π
/
2
∫
1
∞
cos
θ
r
3
r
d
r
d
θ
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Find the (exact) direction cosines and (rounded to 1 decimal place) direction angles of = (3,7,6)
Let a = (-1, -2, -3) and 6 = (-4, 0, 1).
Find the component of b onto a.
Forces of 9 pounds and 15 pounds act on each other with an angle of 72°.
The magnitude of the resultant force
The resultant force has an angle of
pounds.
* with the 9 pound force.
The resultant force has an angle of
with the 15 pound force.
It is best to calculate each angle separately and check by seeing if they add to 72°.
Chapter 16 Solutions
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