Explanation Given information: The given matrix A is [ 2 − 1 1 − 1 4 − 3 1 − 3 2 ] . Calculation: Use Gauss Jordan method. Write the given matrix with identity matrix. A = [ 2 − 1 1 − 1 4 − 3 1 − 3 2 | 1 0 0 0 1 0 0 0 1 ] (1) The vertical line in Equation (1) denotes the separation of two matrices. The first element in Equation (1) a 11 should be 1. Replace row 1 by dividing 2 with each element of row 1. A = [ 2 − 1 1 − 1 4 − 3 1 − 3 2 | 1 0 0 0 1 0 0 0 1 ] → R 1 → R 1 2 = [ 2 2 − 1 2 1 2 − 1 4 − 3 1 − 3 2 | 1 2 0 2 0 2 0 1 0 0 0 1 ] = [ 1 − 1 2 1 2 − 1 4 − 3 1 − 3 2 | 1 2 0 0 0 1 0 0 0 1 ] (2) The elements a 21 and a 31 in Equation (2) should be 0. Replace the elements of row 2 by adding each element of row 1 from the corresponding element in row 2 and Replace the elements of row 3 by subtracting element of row 1 from the corresponding element in row 3. A = [ 1 − 1 2 1 2 − 1 4 − 3 1 − 3 2 | 1 2 0 0 0 1 0 0 0 1 ] → R 2 = R 2 + R 1 R 3 = R 3 − R 1 = [ 1 − 1 2 1 2 − 1 + ( 1 ) 4 − 1 2 − 3 + 1 2 1 − 1 − 3 − ( − 1 2 ) 2 − 1 2 | 1 2 0 0 0 + 1 2 1 + 0 0 + 0 0 − 1 2 0 − 0 1 − 0 ] = [ 1 − 1 2 1 2 0 7 2 − 5 2 0 − 5 2 3 2 | 1 2 0 0 1 2 1 0 − 1 2 0 1 ] (3) The bottom row element a 22 in Equation (3) should be 1. Replace the row 2 by dividing 7 2 with each element in row 2. A = [ 1 − 1 2 1 2 0 7 2 − 5 2 0 − 5 2 3 2 | 1 2 0 0 1 2 1 0 − 1 2 0 1 ] → R 2 7 2 = [ 1 − 1 2 1 2 0 7 2 7 2 7 2 − 5 2 7 2 0 − 5 2 3 2 | 1 2 0 0 1 2 7 2 1 7 2 0 7 2 − 1 2 0 1 ] = [ 1 − 1 2 1 2 0 1 − 5 7 0 − 5 2 3 2 | 1 2 0 0 1 7 2 7 0 − 1 2 0 1 ] (4) The elements a 12 and a 32 in Equation (4) should be zero. Replace the elements of row 1 by subtracting 1 2 times each element of row 2 from the corresponding element in row 1. Replace the elements of row 3 by adding 5 2 times each element of row 2 from the corresponding element in row 3

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

11th Edition

ISBN: 9780135902912

Author: Allyn J. Washington

Publisher: PEARSON

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Chapter 16.3, Problem 40E

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Chapter 16.3, Problem 39E

Chapter 16.3, Problem 41E

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Chapter 16 Solutions

Mylab Math With Pearson Etext -- 18 Week Standalone Access Card -- For Basic Technical Mathematics With Calculus

Ch. 16.1 - For matrices A and B, find A + B. Ch. 16.1 - Prob. 2PE Ch. 16.1 - Prob. 3PE Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E Ch. 16.1 - In Exercises 3–10, determine the value of the...Ch. 16.1 - Prob. 6E Ch. 16.1 - Prob. 7E

Ch. 16.1 - Prob. 8E Ch. 16.1 - In Exercises 3–10, determine the value of the...Ch. 16.1 - Prob. 10E Ch. 16.1 - Prob. 11E Ch. 16.1 - Prob. 12E Ch. 16.1 - Prob. 13E Ch. 16.1 - Prob. 14E Ch. 16.1 - Prob. 15E Ch. 16.1 - Prob. 16E Ch. 16.1 - Prob. 17E Ch. 16.1 - Prob. 18E Ch. 16.1 - Prob. 19E Ch. 16.1 - Prob. 20E Ch. 16.1 - Prob. 21E Ch. 16.1 - Prob. 22E Ch. 16.1 - Prob. 23E Ch. 16.1 - Prob. 24E Ch. 16.1 - Prob. 25E Ch. 16.1 - Prob. 26E Ch. 16.1 - Prob. 27E Ch. 16.1 - Prob. 28E Ch. 16.1 - Prob. 29E Ch. 16.1 - Prob. 30E Ch. 16.1 - Prob. 31E Ch. 16.1 - Prob. 32E Ch. 16.1 - Prob. 33E Ch. 16.1 - Prob. 34E Ch. 16.1 - Prob. 35E Ch. 16.1 - Prob. 36E Ch. 16.1 - Prob. 37E Ch. 16.1 - Prob. 38E Ch. 16.1 - Prob. 39E Ch. 16.1 - Prob. 40E Ch. 16.1 - Prob. 41E Ch. 16.1 - Prob. 42E Ch. 16.1 - Prob. 43E Ch. 16.1 - Prob. 44E Ch. 16.2 - Prob. 1PE Ch. 16.2 - Prob. 2PE Ch. 16.2 - Prob. 3PE Ch. 16.2 - Prob. 1E Ch. 16.2 - Prob. 2E Ch. 16.2 - Prob. 3E Ch. 16.2 - Prob. 4E Ch. 16.2 - Prob. 5E Ch. 16.2 - Prob. 6E Ch. 16.2 - 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Chapter 16 Solutions