Concept explainers
Average value Use the definition for the average value of a function over a region R(Section 16.1)
96. Find the average value of z = a2 − x2 − y2 over the region
Want to see the full answer?
Check out a sample textbook solutionChapter 16 Solutions
CALCULUS: EARLY TRANSCENDENTALS (LCPO)
Additional Math Textbook Solutions
Pre-Algebra Student Edition
Intro Stats, Books a la Carte Edition (5th Edition)
University Calculus: Early Transcendentals (4th Edition)
College Algebra (7th Edition)
Elementary Statistics
Basic Business Statistics, Student Value Edition
- A soda can is made from 40 square inches of aluminum. Let x denote the radius of the top of the can, and let h denote the height, both in inches. a. Express the total surface area S of the can, using x and h. Note: The total surface area is the area of the top plus the area of the bottom plus the area of the cylinder. b. Using the fact that the total area is 40 square inches, express h in terms of x. c. Express the volume V of the can in terms of x.arrow_forwardA soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in inches. a. Using the fact that the volume of the can is 25 cubic inches, express h in terms of x. b. Express the total surface area S of the can in terms of x.arrow_forwardDo asap please i will give you thumbs up please do.fastarrow_forward
- Show workarrow_forwardQuestion: How are the average rate of change of a function f on the interval [a, a + h] and the secant line through the points (a, f (a)) and (a + h, f (a + h)) on the function f? 2.arrow_forwardSketch the region bounded by the graphs of the functions. y = x2 − x − 12, y = 0, x = −3, x = 3arrow_forward
- Find the area of the shaded regionarrow_forwardNormalize the set of functions "sin, n = 1, 2, 3,..", –d < x < d Useful constants: h= 6.62 x 10-34 J s, c = 3 x 1010 cm s', m, = 9.1 × 10-31 kg, g= 9.8 m s? (sin ax) dx = - -cos ax + C a cos ax) dx = sin ax + C 1 |(sin'ax) dx 1 sin 2ax + C 4a %3D )dx D + sin 2ax + C 2 4a |* sin"az) dx = -(; - sin 2ax - x cos 2ax + C 4a 8a |f cos*ax) dx = +(; sin 2 ax + &a x cos 2ax + C 4a cos 3ax + C 12a 3 cos ax | (sin ax)dx 4a * (sin ax)dx = (a²x² - 2) cos ax 2x sin ax + C a (ax? - 2) sin ax 2x cos ax + C a? x (cos ax)dx =arrow_forwardplease help mearrow_forward
- Can you explain these questions step by step, I've some doubts about how to solve this kind of question!arrow_forwardSurface area of a sphere cylinderarrow_forwardrQuestion 1] a) Evaluate the average rate of change for each function over the given interval: i. f(x) = 4x+5, from x 3 to x 5. ii. f(x) = x +3x+2 from x 2 to x 4 b) Find the gradient of the curve f(x) = x -4x+3 at x 3 2x-3 c) Use the quotient rule to differentiate the function f(x) = d) Rewrite the function as f(x) = (2.r-3)x and differentiate using the Product rule. e) Show that your answer in parts (a) and (b) are the same. Note: Average rate of change = A – V½ -Yf(x,)-f(x,) Ax %3D %3D X-X, ュ-Xarrow_forward
- College AlgebraAlgebraISBN:9781305115545Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage LearningFunctions and Change: A Modeling Approach to Coll...AlgebraISBN:9781337111348Author:Bruce Crauder, Benny Evans, Alan NoellPublisher:Cengage LearningAlgebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage