Explanation Given : f ( x , y ) = x , Domain D as region over 0 ≤ x ≤ 1 , 1 ≤ y ≤ e x 2 Calculation : Step 1: The given inequalities describe D as a vertically simple region Step 2: Computing the double integral of f ( x , y ) = x on D by the following iterated integral, we get ∫ ∫ D x d A = ∫ 0 1 ∫ 1 e x 2 x d y d x = ∫ 0 1 x y | y = 1 e x 2 d x = ∫ 0 1 ( x e x 2 − x ...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Question

Chapter 16.2, Problem 19E

To determine

The value of the double integral of $f (x, y) = x$ over the domain D indicated as $0 \leq x \leq 1, 1 \leq y \leq e^{x^{2}}$

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Chapter 16.2, Problem 18E

Chapter 16.2, Problem 20E

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Chapter 16 Solutions

Calculus - Standalone book

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Knowledge Booster

The value of the double integral of f ( x , y ) = x over the domain D indicated as 0 ≤ x ≤ 1 , 1 ≤ y ≤ e x 2

Solution Summary: The author explains how the double integral of f (x, y) = x over the domain D is computed to be approximately 0.359.

The value of the double integral of $f (x, y) = x$ over the domain D indicated as $0 \leq x \leq 1, 1 \leq y \leq e^{x^{2}}$

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Chapter 16 Solutions

The value of the double integral of f ( x , y ) = x over the domain D indicated as 0 ≤ x ≤ 1 , 1 ≤ y ≤ e x 2

Solution Summary: The author explains how the double integral of f (x, y) = x over the domain D is computed to be approximately 0.359.

The value of the double integral of f(x,y)=x over the domain D indicated as 0≤x≤1,1≤y≤ex2

Want to see the full answer?

Chapter 16 Solutions

The value of the double integral of $f (x, y) = x$ over the domain D indicated as $0 \leq x \leq 1, 1 \leq y \leq e^{x^{2}}$