Explanation Given: The probability distribution: p ( x , y ) = { C ( 4 x − y + 3 ) if 0 ≤ x ≤ 2 , 0 ≤ y ≤ 3 0 otherwise } Calculation: Consider the probability distribution p ( x , y ) = { C ( 4 x − y + 3 ) if 0 ≤ x ≤ 2 , 0 ≤ y ≤ 3 0 otherwise } Since it is a joint probability distribution, ∫ 0 2 ∫ 0 3 p ( x , y ) d y d x = 1 ∫ 0 2 ∫ 0 3 C ( 4 x − y + 3 ) d y d x = 1 C ∫ 0 2 [ ( 4 x + 3 ) y − y 2 2 ] 0 3 d x = 1 C ∫ 0 2 [ ( 4 x + 3 ) ( 3 − 0 ) − 1 2 ( 3 2 − 0 2 ) ] d x = 1 C ∫ 0 2 [ 12 x + 9 − 9 2 ] d x = 1 C ∫ 0 2 [ 24 x + 9 2 ] d x = 1 C 2 [ 24...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could co…

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Chapter 16, Problem 53CRE

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$P (3 X + 2 Y \geq 6)$

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Chapter 16, Problem 52CRE

Chapter 16, Problem 54CRE

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Chapter 16 Solutions

Calculus - Standalone book

Ch. 16.1 - Prob. 1PQ Ch. 16.1 - Prob. 2PQ Ch. 16.1 - Prob. 3PQ Ch. 16.1 - Prob. 4PQ Ch. 16.1 - Prob. 5PQ Ch. 16.1 - Prob. 6PQ Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E

Ch. 16.1 - Prob. 5E Ch. 16.1 - Prob. 6E Ch. 16.1 - Prob. 7E Ch. 16.1 - Prob. 8E Ch. 16.1 - Prob. 9E Ch. 16.1 - Prob. 10E Ch. 16.1 - Prob. 11E Ch. 16.1 - Prob. 12E Ch. 16.1 - Prob. 13E Ch. 16.1 - Prob. 14E Ch. 16.1 - Prob. 15E Ch. 16.1 - Prob. 16E Ch. 16.1 - Prob. 17E Ch. 16.1 - Prob. 18E Ch. 16.1 - Prob. 19E Ch. 16.1 - Prob. 20E Ch. 16.1 - Prob. 21E Ch. 16.1 - Prob. 22E Ch. 16.1 - Prob. 23E Ch. 16.1 - Prob. 24E Ch. 16.1 - Prob. 25E Ch. 16.1 - Prob. 26E Ch. 16.1 - Prob. 27E Ch. 16.1 - Prob. 28E Ch. 16.1 - Prob. 29E Ch. 16.1 - Prob. 30E Ch. 16.1 - Prob. 31E Ch. 16.1 - Prob. 32E Ch. 16.1 - Prob. 33E Ch. 16.1 - Prob. 34E Ch. 16.1 - Prob. 35E Ch. 16.1 - Prob. 36E Ch. 16.1 - Prob. 37E Ch. 16.1 - Prob. 38E Ch. 16.1 - Prob. 39E Ch. 16.1 - Prob. 40E Ch. 16.1 - Prob. 41E Ch. 16.1 - Prob. 42E Ch. 16.1 - Prob. 43E Ch. 16.1 - Prob. 44E Ch. 16.1 - Prob. 45E Ch. 16.1 - Prob. 46E Ch. 16.1 - Prob. 47E Ch. 16.1 - Prob. 48E Ch. 16.1 - Prob. 49E Ch. 16.1 - Prob. 50E Ch. 16.1 - Prob. 51E Ch. 16.1 - Prob. 52E Ch. 16.1 - 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Prob. 57E Ch. 16.5 - Prob. 58E Ch. 16.5 - Prob. 59E Ch. 16.5 - Prob. 60E Ch. 16.5 - Prob. 61E Ch. 16.5 - Prob. 62E Ch. 16.5 - Prob. 63E Ch. 16.5 - Prob. 64E Ch. 16.6 - Prob. 1PQ Ch. 16.6 - Prob. 2PQ Ch. 16.6 - Prob. 3PQ Ch. 16.6 - Prob. 4PQ Ch. 16.6 - Prob. 1E Ch. 16.6 - Prob. 2E Ch. 16.6 - Prob. 3E Ch. 16.6 - Prob. 4E Ch. 16.6 - Prob. 5E Ch. 16.6 - Prob. 6E Ch. 16.6 - Prob. 7E Ch. 16.6 - Prob. 8E Ch. 16.6 - Prob. 9E Ch. 16.6 - Prob. 10E Ch. 16.6 - Prob. 11E Ch. 16.6 - Prob. 12E Ch. 16.6 - Prob. 13E Ch. 16.6 - Prob. 14E Ch. 16.6 - Prob. 15E Ch. 16.6 - Prob. 16E Ch. 16.6 - Prob. 17E Ch. 16.6 - Prob. 18E Ch. 16.6 - Prob. 19E Ch. 16.6 - Prob. 20E Ch. 16.6 - Prob. 21E Ch. 16.6 - Prob. 22E Ch. 16.6 - Prob. 23E Ch. 16.6 - Prob. 24E Ch. 16.6 - Prob. 25E Ch. 16.6 - Prob. 26E Ch. 16.6 - Prob. 27E Ch. 16.6 - Prob. 28E Ch. 16.6 - Prob. 29E Ch. 16.6 - Prob. 30E Ch. 16.6 - Prob. 31E Ch. 16.6 - Prob. 32E Ch. 16.6 - Prob. 33E Ch. 16.6 - Prob. 34E Ch. 16.6 - Prob. 35E Ch. 16.6 - Prob. 36E Ch. 16.6 - Prob. 37E Ch. 16.6 - Prob. 38E Ch. 16.6 - Prob. 39E Ch. 16.6 - Prob. 40E Ch. 16.6 - Prob. 41E Ch. 16.6 - Prob. 42E Ch. 16.6 - Prob. 43E Ch. 16.6 - Prob. 44E Ch. 16.6 - Prob. 45E Ch. 16.6 - Prob. 46E Ch. 16.6 - Prob. 47E Ch. 16.6 - Prob. 48E Ch. 16.6 - Prob. 49E Ch. 16.6 - Prob. 50E Ch. 16.6 - Prob. 51E Ch. 16.6 - Prob. 52E Ch. 16 - Prob. 1CRE Ch. 16 - Prob. 2CRE Ch. 16 - Prob. 3CRE Ch. 16 - Prob. 4CRE Ch. 16 - Prob. 5CRE Ch. 16 - Prob. 6CRE Ch. 16 - Prob. 7CRE Ch. 16 - Prob. 8CRE Ch. 16 - Prob. 9CRE Ch. 16 - Prob. 10CRE Ch. 16 - Prob. 11CRE Ch. 16 - Prob. 12CRE Ch. 16 - Prob. 13CRE Ch. 16 - Prob. 14CRE Ch. 16 - Prob. 15CRE Ch. 16 - Prob. 16CRE Ch. 16 - Prob. 17CRE Ch. 16 - Prob. 18CRE Ch. 16 - Prob. 19CRE Ch. 16 - Prob. 20CRE Ch. 16 - Prob. 21CRE Ch. 16 - Prob. 22CRE Ch. 16 - Prob. 23CRE Ch. 16 - Prob. 24CRE Ch. 16 - Prob. 25CRE Ch. 16 - Prob. 26CRE Ch. 16 - Prob. 27CRE Ch. 16 - Prob. 28CRE Ch. 16 - Prob. 29CRE Ch. 16 - Prob. 30CRE Ch. 16 - Prob. 31CRE Ch. 16 - Prob. 32CRE Ch. 16 - Prob. 33CRE Ch. 16 - Prob. 34CRE Ch. 16 - Prob. 35CRE Ch. 16 - Prob. 36CRE Ch. 16 - Prob. 37CRE Ch. 16 - Prob. 38CRE Ch. 16 - Prob. 39CRE Ch. 16 - Prob. 40CRE Ch. 16 - Prob. 41CRE Ch. 16 - Prob. 42CRE Ch. 16 - Prob. 43CRE Ch. 16 - Prob. 44CRE Ch. 16 - Prob. 45CRE Ch. 16 - Prob. 46CRE Ch. 16 - Prob. 47CRE Ch. 16 - Prob. 48CRE Ch. 16 - Prob. 49CRE Ch. 16 - Prob. 50CRE Ch. 16 - Prob. 51CRE Ch. 16 - Prob. 52CRE Ch. 16 - Prob. 53CRE Ch. 16 - Prob. 54CRE Ch. 16 - Prob. 55CRE Ch. 16 - Prob. 56CRE Ch. 16 - Prob. 57CRE Ch. 16 - Prob. 58CRE Ch. 16 - Prob. 59CRE Ch. 16 - Prob. 60CRE Ch. 16 - Prob. 61CRE

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P ( 3 X + 2 Y ≥ 6 )

Solution Summary: The author calculates P ( 3 X + 2 Y 6 ) = 19 33, since it is a joint probability distribution.

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$P (3 X + 2 Y \geq 6)$

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Chapter 16 Solutions

P ( 3 X + 2 Y ≥ 6 )

Solution Summary: The author calculates P ( 3 X + 2 Y 6 ) = 19 33, since it is a joint probability distribution.

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To calculate: P(3X+2Y≥6)

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Chapter 16 Solutions

To calculate:

$P (3 X + 2 Y \geq 6)$