Concept explainers
(a)
Interpretation:
The main structural difference between amylose and cellulose is to be stated.
Concept Introduction:
Glycosidic bond is the bond present between two monosaccharide molecules which are bonded together to form a disaccharide molecule. If both the monosaccharide molecules are connected through equatorial-equatorial or axial-axial positions, then the linkages present are alpha linkages and the sugars connected through axial-equatorial positions, then the linkage is beta linkage.
(b)
Interpretation:
The main structural difference between amylose and amylopectin is to be stated.
Concept Introduction:
Glycosidic bond is the bond present between two monosaccharide molecules which are bonded together to form a disaccharide molecule. If both the monosaccharide molecules are connected through equatorial-equatorial or axial-axial positions, then the linkages present are alpha linkages and the sugars connected through axial-equatorial positions, then the linkage is beta linkage.
(c)
Interpretation:
The main structural difference between amylopectin and glycogen is to be stated.
Concept Introduction:
Glycosidic bond is the bond present between two monosaccharide molecules which are bonded together to form a disaccharide molecule. If both the monosaccharide molecules are connected through equatorial-equatorial or axial-axial positions, then the linkages present are alpha linkages and the sugars connected through axial-equatorial positions, then the linkage is beta linkage.
(d)
Interpretation:
The main structural difference between cellulose and chitin is to be stated.
Concept Introduction:
Glycosidic bond is the bond present between two monosaccharide molecules which are bonded together to form a disaccharide molecule. If both the monosaccharide molecules are connected through equatorial-equatorial or axial-axial positions, then the linkages present are alpha linkages and the sugars connected through axial-equatorial positions, then the linkage is beta linkage.
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Chapter 16 Solutions
EBK ESSENTIAL ORGANIC CHEMISTRY
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- Draw the principal organic product of the following reaction.arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided structures, draw the curved arrows that epict the mechanistic steps for the proton transfer between a hydronium ion and a pi bond. Draw any missing organic structures in the empty boxes. Be sure to account for all lone-pairs and charges as well as bond-breaking and bond-making steps. 2 56°F Mostly cloudy F1 Drawing Arrows > Q Search F2 F3 F4 ▷11 H. H : CI: H + Undo Reset Done DELLarrow_forwardCalculate the chemical shifts in 13C and 1H NMR for 4-chloropropiophenone ? Write structure and label hydrogens and carbons. Draw out the benzene ring structure when doing itarrow_forward
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