Cylinders Let S be the solid in ℝ 3 between the cylinder z = f ( x ) and the region, where f ( x ) ≥ 0 on R. Explain why ∫ c d ∫ a b f ( x ) d x d y equals the area of the constant cross section of S multiplied by (d – c), which is the volume of S.
Cylinders Let S be the solid in ℝ 3 between the cylinder z = f ( x ) and the region, where f ( x ) ≥ 0 on R. Explain why ∫ c d ∫ a b f ( x ) d x d y equals the area of the constant cross section of S multiplied by (d – c), which is the volume of S.
Solution Summary: The author explains that the volume of the solid is equal to the (d-c) times the area of a constant cross section.
Cylinders Let S be the solid in
ℝ
3
between the cylinder z = f(x) and the region, where f(x) ≥ 0 on R. Explain why
∫
c
d
∫
a
b
f
(
x
)
d
x
d
y
equals the area of the constant cross section of S multiplied by (d – c), which is the volume of S.
Two cables tied together at C are loaded as shown. Given: Q = 130 lb.
8
30°
C
B
Q
3
4
Draw the free-body diagram needed to determine the range of values of P for which both cables remain taut.
Cable AB is 103 ft long and the tension in the cable is 3900 lb.
56 ft
A
50°
20°
B
x
C
Identify the angles 0.0, and 8, that define the direction of force.
1
By
N
2
Match each of the options above to the items below.
142.1°
57.1°
73.3°
3
8.
In the given figure, P = 51 lb .
65°
C
25°
35°
75 lb
P
Determine the corresponding magnitude of the resultant.
The corresponding magnitude of the resultant is|
lb.
Chapter 16 Solutions
Calculus: Early Transcendentals, Books A La Carte Edition (3rd Edition)
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Area Between The Curve Problem No 1 - Applications Of Definite Integration - Diploma Maths II; Author: Ekeeda;https://www.youtube.com/watch?v=q3ZU0GnGaxA;License: Standard YouTube License, CC-BY