Explanation Given information: The mass of the roll ( m ) is 1200 kg . The diameter of the roll ( d ) is 100 mm . The tension of the cable A ( T A ) is 3100 N . The tension of the cable B ( T B ) is 3300 N . The radius of gyration of the roll ( k ) is 150 mm . Calculation: Consider the acceleration due to gravity ( g ) as 9.81 m / s 2 . Convert the unit of the radius of gyration of the roll ( k ) : k = 150 mm × 10 − 3 m 1 mm = 0.15 m Calculate the radius of the roll ( r ) : r = d 2 Substitute 100 mm for d . r = 100 2 = 50 mm × 10 − 3 m 1 mm = 0.05 m Calculate the mass moment of inertia of the roll ( I ¯ ) : I ¯ = m k 2 Substitute 1200 kg for m and 0.15 m for k To determine Find the acceleration of the mass center of the roll ( a ) .

12th Edition

ISBN: 9781265566296

Author: BEER

Publisher: MCG

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Chapter 16.1, Problem 16.58P

To determine

Find the angular acceleration of the roll (α).

To determine

Find the acceleration of the mass center of the roll (a).

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Chapter 16.1, Problem 16.57P

Chapter 16.1, Problem 16.59P

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Find the angular acceleration of the roll ( α ) .

Solution Summary: The author calculates the radius of gyration of the roll (k).