Explanation The mass of the bar AB ( m A B ) is 4 kg . The mass of the bar BE ( m B E ) is 4 kg . The length of the bar AB ( L A B ) is 0.5 m . The length of the bar BE ( L B E ) is 0.5 m . Calculation: Consider the acceleration due to gravity ( g ) is 9.81 m / s 2 . Refer the problem 16.14. The bar AB: Show the free body diagram of the portion of the bar AB as in Figure 1. Here, u is the distance between point A and J , F A is the force at the point A , T is the tension of the bar AB , M is the bending moment of the bar AB and V is the shear force of the bar AB . Refer to Figure 1 Calculate the forces at the normal: ∑ F n = 0 − V = m a n − V = 4 0.5 × u × g 2 × 3 2 − V = 2 3 g u Substitute 9.81 m / s 2 for g . V = − 2 3 × 9.81 × u = − 33.983 u (1) Calculate the moment about point J by applying the equation of equilibrium: ∑ M J = I G α + m a d M = 33.983 u × u 2 M = 16.991 u 2 (2) Consider the distance, u = 0.5 m . Calculate the shear force for the bar AB ( V ) : Substitute 0.5 m for u in Equation (1). V = − 33.983 × 0.5 = − 16.991 N Calculate the maximum bending moment for the bar AB ( M ) : Substitute 0.5 m for u in Equation (2). M = 16

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Author: BEER

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Chapter 16.1, Problem 16.22P

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Draw the shear and bending-moment diagrams for each of the bars AB and BE.

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Draw the shear and bending-moment diagrams for each of the bars AB and BE .

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