Explanation Given info: The loudspeaker A and B are having same amplifier and emit sinusoidal waves in phase, the frequency of the waves emitted by each speaker is 860 Hz , the point P is 12.0 m from A and 13.4 m from B and the speed of the sound in air is 344 m/s . The fully constructive interface occurs when, Δ L λ = 0 , 1 , 2 , 3 , ⋅ ⋅ ⋅ (I) Δ L is the path difference. λ is the wavelength. x is the interface. The fully destructive interface occurs when, Δ L λ = 0.5 , 1.5 , 2.5 , 3.5 ⋅ ⋅ ⋅ (II) Formula to calculate the path difference of speaker A and B at the point P is, Δ L = L 2 − L 1 Δ L is the path difference. L 2 is the distance of the point P from B . L 1 is the distance of the point P from A . Substitute 13.4 m for L 2 and 12

14th Edition

ISBN: 9780133969290

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Chapter 16, Problem Q16.15DQ

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The interface at the point P is whether constructive or destructive.

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Chapter 16, Problem Q16.14DQ

Chapter 16, Problem Q16.16DQ

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The interface at the point P is whether constructive or destructive.

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The interface at the point P is whether constructive or destructive.

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