INTRODUCTORY CHEMISTRY
INTRODUCTORY CHEMISTRY
9th Edition
ISBN: 9780357858998
Author: ZUMDAHL
Publisher: CENGAGE C
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Chapter 16, Problem 95AP
Interpretation Introduction

(a)

Interpretation:

The concentration of hydroxide ion OH should be calculated. If the solution is acidic, neutral or basic should be indicated.

Concept Introduction:

The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic.

The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows:

pH=logH+

Here, H+ is concentration of hydrogen ion.

Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows:

pOH=logOH

Here, OH is concentration of hydroxide ion.

pH and pOH of a solution are related to each other as follows:

pH+pOH=14

In a pH scale, if the value of pH is below 7 the solution is said to be acidic in nature, if the pH value is above 7 it is said to be basic in nature. At pH 7, the solution is neutral.

Expert Solution
Check Mark

Answer to Problem 95AP

2.4×108 M, Acidic.

Explanation of Solution

Given Information:

The concentration of hydrogen ion is 4.21×107 M

Calculation:

From the given hydrogen ion concentration, pH of solution can be calculated as follows:

pH=logH+

Putting the values,

pH=log4.21×107=6.38

From the pH, pOH of solution can be calculated as follows:

pOH=14pH

Putting the value,

pOH=146.38=7.62

Thus, concentration of hydroxide ion will be:

pOH=logOH

On rearranging,

OH=10pOH

Putting the value,

OH=107.62=2.4×108 M

Thus, concentration of hydroxide ion is 2.4×108 M.

Since, pH of solution is below 7, the solution is acidic in nature.

Interpretation Introduction

(b)

Interpretation:

The concentration of hydroxide ion OH should be calculated. If the solution is acidic, neutral or basic should be indicated.

Concept Introduction:

The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic.

The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows:

pH=logH+

Here, H+ is concentration of hydrogen ion.

Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows:

pOH=logOH

Here, OH is concentration of hydroxide ion.

pH and pOH of a solution are related to each other as follows:

pH+pOH=14

In a pH scale, if the value of pH is below 7 the solution is said to be acidic in nature, if the pH value is above 7 it is said to be basic in nature. At pH 7, the solution is neutral.

Expert Solution
Check Mark

Answer to Problem 95AP

2.88×1011 M, Acidic.

Explanation of Solution

Given Information:

The concentration of hydrogen ion is 0.00035 M

Calculation:

From the given hydrogen ion concentration, pH of solution can be calculated as follows:

pH=logH+

Putting the values,

pH=log0.00035=3.46

From the pH, pOH of solution can be calculated as follows:

pOH=14pH

Putting the value,

pOH=143.46=10.54

Thus, concentration of hydroxide ion will be:

pOH=logOH

On rearranging,

OH=10pOH

Putting the value,

OH=1010.54=2.88×1011 M

Thus, concentration of hydroxide ion is 2.88×1011 M.

Since, pH of solution is below 7, the solution is acidic in nature.

Interpretation Introduction

(c)

Interpretation:

The concentration of hydroxide ion OH should be calculated. If the solution is acidic, neutral or basic should be indicated.

Concept Introduction:

The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic.

The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows:

pH=logH+

Here, H+ is concentration of hydrogen ion.

Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows:

pOH=logOH

Here, OH is concentration of hydroxide ion.

pH and pOH of a solution are related to each other as follows:

pH+pOH=14

In a pH scale, if the value of pH is below 7 the solution is said to be acidic in nature, if the pH value is above 7 it is said to be basic in nature. At pH 7, the solution is neutral.

Expert Solution
Check Mark

Answer to Problem 95AP

1.0×107 M, Neutral.

Explanation of Solution

Given Information:

The concentration of hydrogen ion is 0.00000010 M

Calculation:

From the given hydrogen ion concentration, pH of solution can be calculated as follows:

pH=logH+

Putting the values,

pH=log0.00000010=7

From the pH, pOH of solution can be calculated as follows:

pOH=14pH

Putting the value,

pOH=147=7.0

Thus, concentration of hydroxide ion will be:

pOH=logOH

On rearranging,

OH=10pOH

Putting the value,

OH=107=1×107 M

Thus, concentration of hydroxide ion is 1.0×107 M.

Since, pH of solution is equal to 7, the solution is neutral in nature.

Interpretation Introduction

(d)

Interpretation:

The concentration of hydroxide ion OH should be calculated. If the solution is acidic, neutral or basic should be indicated.

Concept Introduction:

The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic.

The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows:

pH=logH+

Here, H+ is concentration of hydrogen ion.

Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows:

pOH=logOH

Here, OH is concentration of hydroxide ion.

pH and pOH of a solution are related to each other as follows:

pH+pOH=14

In a pH scale, if the value of pH is below 7 the solution is said to be acidic in nature, if the pH value is above 7 it is said to be basic in nature. At pH 7, the solution is neutral.

Expert Solution
Check Mark

Answer to Problem 95AP

1.0×109 M, Acidic.

Explanation of Solution

Given Information:

The concentration of hydrogen ion is 9.9×106 M

Calculation:

From the given hydrogen ion concentration, pH of solution can be calculated as follows:

pH=logH+

Putting the values,

pH=log9.9×106=5

From the pH, pOH of solution can be calculated as follows:

pOH=14pH

Putting the value,

pOH=145=9

Thus, concentration of hydroxide ion will be:

pOH=logOH

On rearranging,

OH=10pOH

Putting the value,

OH=109=1.0×109 M

Thus, concentration of hydroxide ion is 1.0×109 M.

Since, pH of solution is below 7, the solution is acidic in nature.

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Chapter 16 Solutions

INTRODUCTORY CHEMISTRY

Ch. 16 - Explain why Cl- does not affect the pH of an...Ch. 16 - Write the general reaction for an acid acting in...Ch. 16 - Differentiate among the terms concentrated,...Ch. 16 - What is meant by “pH”? True or false: A strong...Ch. 16 - Consider two separate solutions: one containing a...Ch. 16 - Prob. 7ALQCh. 16 - Prob. 8ALQCh. 16 - Stanley’s grade-point average (GPA) is 3.28. What...Ch. 16 - Prob. 10ALQCh. 16 - . Mixing together aqueous solutions of acetic acid...Ch. 16 - Prob. 12ALQCh. 16 - . Consider the equation:...Ch. 16 - . Choose the answer that best completes the...Ch. 16 - Prob. 15ALQCh. 16 - . The following figures are molecular-level...Ch. 16 - Prob. 17ALQCh. 16 - What are some physical properties that...Ch. 16 - Write an equation showing how HCl(g) behaves as an...Ch. 16 - Prob. 3QAPCh. 16 - How do the components of a conjugate acid—base...Ch. 16 - 5. Given the general equation illustrating the...Ch. 16 - According to Arrhenius, ____________ produce...Ch. 16 - Which of the following do not represent a...Ch. 16 - Which of the following do not represent a...Ch. 16 - In each of the following chemical equations,...Ch. 16 - . In each of the following chemical equations,...Ch. 16 - . Write the conjugate acid for each of the...Ch. 16 - . Write the conjugate acid for each of the...Ch. 16 - Prob. 13QAPCh. 16 - . Write the conjugate base for each of the...Ch. 16 - . Write a chemical equation showing how each of...Ch. 16 - . Write a chemical equation showing how each of...Ch. 16 - . What does it mean to say that an acid is strong...Ch. 16 - Prob. 18QAPCh. 16 - . How is the strength of an acid related to the...Ch. 16 - . A strong acid has a weak conjugate base, whereas...Ch. 16 - . Write the formula for the hydronium ion. Write...Ch. 16 - Prob. 22QAPCh. 16 - . Organic acids contain the carboxyl group Using...Ch. 16 - Prob. 24QAPCh. 16 - 25. Which of the following acids have relatively...Ch. 16 - . The “Chemistry in Focus” segment Plants Fight...Ch. 16 - . Water is the most common amphoteric substance,...Ch. 16 - . Anions containing hydrogen (for example. HCO3and...Ch. 16 - . What is meant by the iou-product constant for...Ch. 16 - . What happens to the hydroxide ion concentration...Ch. 16 - Prob. 31QAPCh. 16 - Prob. 32QAPCh. 16 - . Calculate the [OH-] in each of the following...Ch. 16 - . Calculate the [OH-] in each of the following...Ch. 16 - 35. For each pair of concentrations, tell which...Ch. 16 - . For each pair of concentrations, tell which...Ch. 16 - . Why do scientists tend to express the acidity of...Ch. 16 - . Using Fig. 16.3, list the approximate pH value...Ch. 16 - . For a hydrogen ion concentration of 2.33106M,...Ch. 16 - . The “Chemistry in Focus” segment Garden-Variety...Ch. 16 - . Calculate the pH corresponding to each of the...Ch. 16 - Prob. 42QAPCh. 16 - Prob. 43QAPCh. 16 - Prob. 44QAPCh. 16 - Prob. 45QAPCh. 16 - . Calculate the pOH value corresponding to each of...Ch. 16 - . For each hydrogen ion concentration listed,...Ch. 16 - . For each hydrogen ion concentration listed,...Ch. 16 - . Calculate the hydrogen ion concentration, in...Ch. 16 - . Calculate the hydrogen ion concentration, in...Ch. 16 - . Calculate the hydrogen ion concentration, in...Ch. 16 - . Calculate the hydrogen ion concentration, in...Ch. 16 - . Calculate the pH of each of the following...Ch. 16 - Prob. 54QAPCh. 16 - 55. When 1 mole of gaseous hydrogen chloride is...Ch. 16 - . A bottle of acid solution is labeled “3 M HNO3.”...Ch. 16 - . Calculate the hydrogen ion concentration and the...Ch. 16 - . Calculate the pH of each of the following...Ch. 16 - . What characteristic properties do buffered...Ch. 16 - Prob. 60QAPCh. 16 - . Which component of a buffered solution is...Ch. 16 - Prob. 62QAPCh. 16 - . Which of the following combinations would act as...Ch. 16 - . A buffered solution is prepared containing...Ch. 16 - . The concepts of acid-base equilibria were...Ch. 16 - . Strong buses are bases that completely ionize in...Ch. 16 - Prob. 67APCh. 16 - Prob. 68APCh. 16 - Prob. 69APCh. 16 - Prob. 70APCh. 16 - Prob. 71APCh. 16 - Prob. 72APCh. 16 - Prob. 73APCh. 16 - Prob. 74APCh. 16 - 75. A conjugate acid-base pair Consists of two...Ch. 16 - . Acetate ion, C2H3O2- , has a stronger affinity...Ch. 16 - Prob. 77APCh. 16 - Prob. 78APCh. 16 - Prob. 79APCh. 16 - Prob. 80APCh. 16 - Prob. 81APCh. 16 - Prob. 82APCh. 16 - Prob. 83APCh. 16 - Prob. 84APCh. 16 - . A(n) _________ solution contains a conjugate...Ch. 16 - . When sodium hydroxide, NaOH, is added dropwise...Ch. 16 - . When hydrochloric acid, HCI. is added dropwise...Ch. 16 - . The following are representations of acid-base...Ch. 16 - . In each of the following chemical equations,...Ch. 16 - Prob. 90APCh. 16 - . Write the conjugate base for each of the...Ch. 16 - . Of the following combinations, which would act...Ch. 16 - Prob. 93APCh. 16 - . Calculate [H+] in each of the following...Ch. 16 - Prob. 95APCh. 16 - . Calculate the pH corresponding to each of the...Ch. 16 - Prob. 97APCh. 16 - Prob. 98APCh. 16 - Prob. 99APCh. 16 - . For each hydrogen or hydroxide ion concentration...Ch. 16 - . Calculate the hydrogen ion concentration, in...Ch. 16 - Prob. 102APCh. 16 - Prob. 103APCh. 16 - Prob. 104APCh. 16 - . Write the formulas for three combinations of...Ch. 16 - . Choose pairs in which the species listed first...Ch. 16 - . Complete the table for each of the following...Ch. 16 - . Consider 0.25 M solutions of the following...
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