A Double-Paned Window An energy-efficient double-paned window consists of two panes of glass seen with thickness L 1 and thermal conductivity k 1 , separated by a layer of air of thickness L 2 and thermal conductivity k 2 . Show that the equilibrium rate of heat flow through this window per unit area, A, is Q A t = ( T 2 − T 1 ) 2 L 1 / k 1 + L 2 / k 2 In this expression, T 1 and T 2 are the temperatures on either side of the window.
A Double-Paned Window An energy-efficient double-paned window consists of two panes of glass seen with thickness L 1 and thermal conductivity k 1 , separated by a layer of air of thickness L 2 and thermal conductivity k 2 . Show that the equilibrium rate of heat flow through this window per unit area, A, is Q A t = ( T 2 − T 1 ) 2 L 1 / k 1 + L 2 / k 2 In this expression, T 1 and T 2 are the temperatures on either side of the window.
A Double-Paned Window An energy-efficient double-paned window consists of two panes of glass seen with thickness L1 and thermal conductivityk1, separated by a layer of air of thickness L2 and thermal conductivity k2. Show that the equilibrium rate of heat flow through this window per unit area, A, is
Q
A
t
=
(
T
2
−
T
1
)
2
L
1
/
k
1
+
L
2
/
k
2
In this expression, T1 and T2 are the temperatures on either side of the window.
A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).
What are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V)
ammeter
I =
simple diagram to illustrate the setup for each law- coulombs law and biot savart law
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The Second Law of Thermodynamics: Heat Flow, Entropy, and Microstates; Author: Professor Dave Explains;https://www.youtube.com/watch?v=MrwW4w2nAMc;License: Standard YouTube License, CC-BY