The equilibrium constant for the following reaction is 1.0 × 10 23 : Cr 3+ ( a q ) + H 2 E D T A 2 − ( a q ) ⇌ C r E D T A − ( a q ) + 2 H + ( a q ) EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt Na 2 H 2 EDTA, are used to treat heavy metal poisoning. Calculate [Cr 3+ ] at equilibrium in a solution originally 0.0010 M in Cr 3+ and 0.050 M in H 2 EDTA 2− and buffered at pH = 6.00.
The equilibrium constant for the following reaction is 1.0 × 10 23 : Cr 3+ ( a q ) + H 2 E D T A 2 − ( a q ) ⇌ C r E D T A − ( a q ) + 2 H + ( a q ) EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt Na 2 H 2 EDTA, are used to treat heavy metal poisoning. Calculate [Cr 3+ ] at equilibrium in a solution originally 0.0010 M in Cr 3+ and 0.050 M in H 2 EDTA 2− and buffered at pH = 6.00.
Solution Summary: The author calculates the value of left[Cr+right] at equilibrium in a solution.
The equilibrium constant for the following reaction is 1.0 × 1023:
Cr
3+
(
a
q
)
+
H
2
E
D
T
A
2
−
(
a
q
)
⇌
C
r
E
D
T
A
−
(
a
q
)
+
2
H
+
(
a
q
)
EDTA is used as a complexing agent in chemical analysis. Solutions of EDTA, usually containing the disodium salt Na2H2EDTA, are used to treat heavy metal poisoning. Calculate [Cr3+] at equilibrium in a solution originally 0.0010 M in Cr3+ and 0.050 M in H2EDTA2− and buffered at pH = 6.00.
6. The equilibrium constant for the reaction
2 HBr (g)
→ H2(g) + Br2(g)
Can be expressed by the empirical formula
11790 K
In K-6.375 + 0.6415 In(T K-¹)
-
T
Use this formula to determine A,H as a function of temperature. Calculate A,-H at 25 °C and at
100 °C.
3. Nitrosyl chloride, NOCI, decomposes according to
2 NOCI (g) → 2 NO(g)
+ Cl2(g)
Assuming that we start with no moles of NOCl (g) and no NO(g) or Cl2(g), derive an expression
for Kp in terms of the equilibrium value of the extent of reaction, Seq, and the pressure, P.
Given that K₂ = 2.00 × 10-4, calculate Seq/
of
29/no when P = 0.080 bar. What is the new value
по
ƒª/ at equilibrium when P = 0.160 bar? Is this result in accord with Le Châtelier's
Principle?
Consider the following chemical equilibrium:
2SO2(g) + O2(g) = 2SO3(g)
•
Write the equilibrium constant expression for this reaction.
Now compare it to the equilibrium constant expression for the related reaction:
•
.
1
SO2(g) + O2(g) = SO3(g)
2
How do these two equilibrium expressions differ?
What important principle about the dependence of equilibrium constants on the stoichiometry of a
reaction can you learn from this comparison?
Chapter 16 Solutions
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