The value of ion-product for water should be determined at 25 ∘ C . Concept Introduction: The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic. The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows: p H = − log H + Here, H + is concentration of hydrogen ion. Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows: p O H = − log OH − Here, OH − is concentration of hydroxide ion. pH and pOH of a solution are related to each other as follows: p H + p O H = 14 In a pH scale, if the value of pH is below 7 the solution is said to be acidic in nature, if the pH value is above 7 it is said to be basic in nature. At pH 7, the solution is neutral.
The value of ion-product for water should be determined at 25 ∘ C . Concept Introduction: The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic. The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows: p H = − log H + Here, H + is concentration of hydrogen ion. Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows: p O H = − log OH − Here, OH − is concentration of hydroxide ion. pH and pOH of a solution are related to each other as follows: p H + p O H = 14 In a pH scale, if the value of pH is below 7 the solution is said to be acidic in nature, if the pH value is above 7 it is said to be basic in nature. At pH 7, the solution is neutral.
Solution Summary: The author explains that the concentration of hydrogen ions in a solution determines the acidity of the solution.
The value of ion-product for water should be determined at 25∘C.
Concept Introduction:
The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic.
The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows:
pH=−logH+
Here, H+ is concentration of hydrogen ion.
Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows:
pOH=−logOH−
Here, OH− is concentration of hydroxide ion.
pH and pOH of a solution are related to each other as follows:
pH+pOH=14
In a pH scale, if the value of pH is below 7 the solution is said to be acidic in nature, if the pH value is above 7 it is said to be basic in nature. At pH 7, the solution is neutral.
Draw the Markovnikov product of the hydrobromination of this alkene.
Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for
this problem.
+
Explanation
Check
1
X
E
4
1
1
1
1
1
HBr
Click and drag to start
drawing a structure.
80
LE
#3
@ 2
$4
0 I
அ2
%
85
F
*
K
M
?
BH
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&
6
27
FG
F10
8
9
R
T
Y
U
D
F
G
H
P
J
K
L
Z
X
C
V B
N
M
Q
W
A
S
H
option
command
H
command
opti
Be sure to use wedge and dash bonds to show the stereochemistry of the products when it's important, for example to distinguish between two different major
products.
Predict the major products of the following reaction.
Explanation
Q
F1
A
Check
F2
@
2
#
3
+
X
80
F3
W
E
S
D
$
4
I O
H.
H₂
2
R
Pt
%
05
LL
ee
F6
F5
T
<6
G
Click and drag to start
drawing a structure.
27
&
A
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Privacy Center Acce
Y
U
H
DII
8
9
F10
4
J
K
L
Z
X
C
V
B
N
M
T
H
option
command
F11
P
H
command
Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow
the arrows to draw the intermediate and product in this reaction or mechanistic step(s).
Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore inorganic byproducts.
H
:0:
CH3
O:
OH
Q
CH3OH2+
Draw Intermediate
protonation
CH3OH
CH3OH
nucleophilic addition
H
Draw Intermediate
deprotonation
:0:
H3C
CH3OH2*
protonation
H
0:
H
CH3
H.
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell