Double integrals—transformation given To evaluate the following integrals, carry out the following steps . a. Sketch the original region of integration R and the new region S using the given change of variables . b. Find the limits of integration for the new integral with respect to u and v . c. Compute the Jacobian . d. Chance variables and evaluate the new integral . 74. ∬ R 3 x y 2 d A ; R = { ( x , y ) : 0 ≤ x ≤ 2 , x ≤ y ≤ x + 4 } use x = 2 u , y = 4 v + 2 u
Double integrals—transformation given To evaluate the following integrals, carry out the following steps . a. Sketch the original region of integration R and the new region S using the given change of variables . b. Find the limits of integration for the new integral with respect to u and v . c. Compute the Jacobian . d. Chance variables and evaluate the new integral . 74. ∬ R 3 x y 2 d A ; R = { ( x , y ) : 0 ≤ x ≤ 2 , x ≤ y ≤ x + 4 } use x = 2 u , y = 4 v + 2 u
Solution Summary: The author illustrates the region R in xy- plane and region S in the uv-plane.
Double integrals—transformation givenTo evaluate the following integrals, carry out the following steps.
a. Sketch the original region of integration R and the new region S using the given change of variables.
b. Find the limits of integration for the new integral with respect to u and v.
c. Compute the Jacobian.
d.Chance variables and evaluate the new integral.
74.
∬
R
3
x
y
2
d
A
;
R
=
{
(
x
,
y
)
:
0
≤
x
≤
2
,
x
≤
y
≤
x
+
4
}
use x = 2u, y = 4v + 2u
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
According to Newton's law of universal gravitation, the force F between two bodies of constant mass
GmM
m and M is given by the formula F =
, where G is the gravitational constant and d is the
d²
distance between the bodies.
a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to
distance d.
F' (d)
2GmM
b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on
two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation,
rounding to 2 decimal places.
-6.67x10
N/m syntax incomplete.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.
Numerical Integration Introduction l Trapezoidal Rule Simpson's 1/3 Rule l Simpson's 3/8 l GATE 2021; Author: GATE Lectures by Dishank;https://www.youtube.com/watch?v=zadUB3NwFtQ;License: Standard YouTube License, CC-BY