Campbell Biology
12th Edition
ISBN: 9780135188743
Author: Urry
Publisher: PEARSON
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Chapter 16, Problem 6TYU
E. coli cells grown on, 15N medium are transferred to 14N medium and allowed to grow for two more generations (two rounds of
(A) one high-density and one low-density band
(B) one intermediate-density band
(C) one high-density and one intermediate-density band
(D) one low-density and one intermediate-density band
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With regard to Chargaff’s experiment described in Figure shown,answer the following:A. What is the purpose of paper chromatography?B. Explain why it is necessary to remove the bases in order todetermine the base composition of DNA.C. Would Chargaff’s experiments have been convincing if theyhad been done on DNA from only one species? Discuss.
E. coli cells grown on 15N medium are transferred to 14N mediumand allowed to grow for two more generations (two rounds ofDNA replication). DNA extracted from these cells is centrifuged.What density distribution of DNA would you expect in thisexperiment?(A) one high-density and one low-density band(B) one intermediate-density band(C) one high-density and one intermediate-density band(D) one low-density and one intermediate-density band
You're purifying some plasmid DNA from a culture of bacteria and you want to know how pure it is. You measure the optical density at 260 m and 280 m and find the ratio is 2.0. You suspect there is RNA contamination in your preparation, so you treat your preparation with RNase. But the ratio is still 2.0. Protein assays tell you there is no protein in your solution, and no other biological molecules absorb light very efficiently at those wavelengths. What's the explanation?
Chapter 16 Solutions
Campbell Biology
Ch. 16.1 - Given a polynucleotide sequence such as GAATTC,...Ch. 16.1 - VISUAL SKILLS Griffith was trying to develop a...Ch. 16.2 - What role does complementary base pairing play in...Ch. 16.2 - Identify two major functions of DNA pol III in DNA...Ch. 16.2 - Prob. 3CCCh. 16.2 - Prob. 4CCCh. 16.3 - Describe the structure of a nucleosome, the basic...Ch. 16.3 - Prob. 2CCCh. 16.3 - MAKE CONNECTIONS Interphase chromosomes appear to...Ch. 16 - What does it mean wheti we say that the two DNA...
Ch. 16 - DRAW IT Redraw the Punnett Square on The right...Ch. 16 - Prob. 16.3CRCh. 16 - In his work with pneumonia-causing bacteria and...Ch. 16 - What is the basis for tlie difference in how the...Ch. 16 - In analyzing the number of different bases in a...Ch. 16 - The elongation of the leading Strand during DNA...Ch. 16 - In a nucleosome, the DNA is wrapped around (A)...Ch. 16 - E. coli cells grown on, 15N medium are transferred...Ch. 16 - A biochemist isolates, purifies, and combines in a...Ch. 16 - The spontaneous loss of amino groups from adenine...Ch. 16 - MAKE CONNECTIONS Although the proteins that cause...Ch. 16 - EVOLUTION CONNECTION Some bacteria may be able to...Ch. 16 - SCIENTIFIC INQUIRY DRAW IT Model building can be...Ch. 16 - Prob. 12TYUCh. 16 - Prob. 13TYU
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- Can you please help with 1f please picture with 1 graph is for question 1a) picture with 4 graphs is for question 1b) 1a) E. coli DNA and binturong DNA are both 50% G-C. If you randomly shear E. coli DNA into 1000 bp fragments and put it through density gradient equilibrium centrifugation, you will find that all the DNA bands at the same place in the gradient, and if you graph the distribution of DNA fragments in the gradient you will get a single peak (see below). If you perform the same experiment with binturong DNA, you will find that a small fraction of the DNA fragments band separately in the gradient (at a different density) and give rise to a small "satellite" peak on a graph of the distribution of DNA fragments in the gradient (see below). Why do these two DNA samples give different results, when they're both 50% G-C? 1b) If you denatured the random 1000 bp fragments of binturong DNA that you produced in question 1a by heating them to 95ºC, and then cooled them down to 60ºC and…arrow_forwardYou're purifying some plasmid DNA from a culture of bacteria and you want to know how pure it is. You measure the optical density at 260 nm and 280 nm and find the ratio is 2.0. You suspect there is RNA contamination in your preparation, so you treat your preparation with RNase. But the ratio is still 2.0. Protein assays tell you there is no protein in your solution, and no other biological molecules absorb light very efficiently at those wavelengths. What's the explanation?arrow_forwardThe Bacteria Escherichia coli DNA genome has a molecular mass of about 3.1 X 10° D. In your answers, show how you came up to each result? (a) How many base pairs does this bacterium contain? (b) How many full double-helical turns does this DNA contain? (c) How long is this DNA in µm?arrow_forward
- Can you please help with 1c please picture with 1 graph is for question 1a) picture with 4 graphs is for question 1b) 1a) E. coli DNA and binturong DNA are both 50% G-C. If you randomly shear E. coli DNA into 1000 bp fragments and put it through density gradient equilibrium centrifugation, you will find that all the DNA bands at the same place in the gradient, and if you graph the distribution of DNA fragments in the gradient you will get a single peak (see below). If you perform the same experiment with binturong DNA, you will find that a small fraction of the DNA fragments band separately in the gradient (at a different density) and give rise to a small "satellite" peak on a graph of the distribution of DNA fragments in the gradient (see below). Why do these two DNA samples give different results, when they're both 50% G-C? 1b) If you denatured the random 1000 bp fragments of binturong DNA that you produced in question 1a by heating them to 95ºC, and then cooled them down to 60ºC…arrow_forwardExplain the principles behind DNA isolation using silica membrane spin column from Qiagen. 2 After DNA isolation using Qiagen extraction kit, the final flow through was subjected to spectrophotometric measurements. Explain the situation if the absorbances were found to be: i) The absorbance at 260 nm is higher than absorbance at 280 nm? ii) The absorbance at 230 is higher than absorbance at 260 nm?arrow_forwardA solution contains DNA polymerase and the Mg ²+ salts of dATP, dGTP, dCTP, and TTP. The following DNA molecules are added to aliquots of this solution. Which of them would lead to DNA synthesis? (a) A single-stranded closed circle containing 1000 nucleotide units. (b) A double-stranded closed circle containing 1000 nucleotide pairs. (c) A single-stranded closed circle of 1000 nucleotides base-paired to a linear strand of 500 nucleotides with a free 3' -OH terminus. (d) A double-stranded linear molecule of 1000 nucleotide pairs with a free 3’-OH group at each end.arrow_forward
- During agarose gel electrophoresis, why does DNA move through the gel when electric current is applied? because DNA is negatively charged because a charged chemical from the loading buffer is bound to the DNA because DNA is positively charged because DNA absorbs electricityarrow_forwardHow are DNA molecules visualized in a gel after electrophoresis? Why do DNA molecules migrate toward the + electrode? What determines the rate of their migration? What is the effect of PEG on DNA fragments of different sizes? How is this influenced by the concentration of PEG?arrow_forwardWhy was it necessary to mash the strawberries extensively with your hands? (hint: you wouldn’t have to do this step with an animal cells). Why do we treat the cells with soap when conducting DNA extraction? And why do we add salt when doing the DNA extraction?arrow_forward
- Quantification of DNA can be done by using a Nanodrop, a UV spectrophotometer, by measuring its absorbance in units of optical density (OD) (see “Nanodrop Microvolume Quantitation of Nucleic Acids" video in Lab 3 on Laulima). DNA absorbs light most strongly at the ultraviolet wavelength of 260 nm. The absorbance of double stranded DNA (dsDNA) at 260 nm (A260) is used to estimate concentration, with 1.0 OD equal to a dsDNA concentration of 50 µg/ml. Using this information we can calculate the concentration of dsDNA in our extractions using the following formula: dsDNA concentration = 50 µg/ml x OD260 x dilution factor Using the formula provided above, calculate the concentration of dsDNA in an extraction that was diluted 20X and had an A260 reading of 0.64 OD. Show your workarrow_forwardA linear DNA molecule is subjected to complete restriction digestion by (1) EcoRI alone, (2) HindIII alone, and (3) both enzymes together. The DNA fragments are then separated using gel electrophoresis. Results are shown below: (i) (ii) (iii) EcoRI Hindill Both | | — | | 10 kb 9 kb 8 kb 5 kb 2 kb 1 kb How long is the original DNA molecule? How many EcoRI recognition sites does it have? Does the longest EcoRI fragment contain a HindIII restriction site? Explain your answer.arrow_forwardAnswer part C of the following: A) E. coli DNA and binturong DNA are both 50% G-C. If you randomly shear E. coli DNA into 1000 bp fragments and put it through density gradient equilibrium centrifugation, you will find that all the DNA bands at the same place in the gradient, and if you graph the distribution of DNA fragments in the gradient you will get a single peak (see below). If you perform the same experiment with binturong DNA, you will find that a small fraction of the DNA fragments band separately in the gradient (at a different density) and give rise to a small "satellite" peak on a graph of the distribution of DNA fragments in the gradient (see below). Why do these two DNA samples give different results, when they're both 50% G-C? See graph B. B) If you denatured the random 1000 bp fragments of binturong DNA that you produced in question 1a by heating them to 95ºC, and then cooled them down to 60ºC and allowed them to reanneal, you would find that approximately 15% of the…arrow_forward
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