EBK BUSINESS DRIVEN TECHNOLOGY
7th Edition
ISBN: 8220103675451
Author: BALTZAN
Publisher: YUZU
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Expert Solution & Answer
Chapter 16, Problem 6MBD
Explanation of Solution
IPTV:
- It is called as Internet Protocol Television. It has the ability to stream the media continuously.
- It is deployed in subscriber based telecommunications networks with high-speed access channels into end-user premises through set-top boxes or other equipment.
- It is secure and provides reliable delivery to their subscribers.
- It is classified into three groups. They are:
- Live Television
- Time-shifted media
- Video on demand
Advantages of IPTV:
Some of the advantages of IPTV are as follows:
- It provides triple play that is; it requires only one cable for Internet, telephony and television.
- It works on both computers and televisions.
- It is easy to integrate camera systems on the same network.
- It is possible to pause, rewind, and stop the media.
- Programs and services can be adjusted according to the customer requirements...
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Students have asked these similar questions
7. See the code below and solve the following.
public class Test {
public static void main(String[] args) {
int result = 0;
}
result = fn(2,3);
System.out.println("The result is:
+ result);
// fn(x, 1) = x
// fn(x, y)
=
fn(x, y-1) + 2, when y>1
public static int fn(int x, int y) {
if (x <= 1)
return x;
else
return fn(x, y-1) + 2;
}
}
7-1. This program has a bug that leads to infinite recursion. Modify fn(int x, int y) method to fix
the problem. (2 point)
7-2. Manually trace the recursive call, fn(2,3) and show the output (step by step). (2 point)
7-3. Can you identify the Base Case in recursive method fn(int x, int y)? (1 point)
6. See the code below and solve the following.
import java.io.*;
public class DataStream {
}
public static void main(String[] args)
}
DataOutputStream output = new DataOutputStream(new FileOutputStream("temp.dat"));
output.writeUTF("Book1");
output.writeInt(85);
output.writeUTF("Book2");
output.writeInt(125);
output.writeUTF("Book3");
output.writeInt(70);
output.close();
// ToDo: Read all data from temp.dat and print the data to the standard output (monitor)
6-1. This program has a compile error, and the message is “Unhandled exception type
FileNotFoundException". How do you fix this error? (1 point)
6-2. Is FileNotFoundException a checked exception or an unchecked exception? (1 point)
6-3. What is the difference between checked exception and unchecked exception? (1 point)
6-4. Please complete the above program by reading all data from temp.dat and print the data
to the standard output (monitor) by using System.out.print, System.out.println or
System.out.printf method. (2 points)
Write a program that reads a list of integers from input and determines if the list is a palindrome (values are identical from first to last and last to first). The input begins with an integer indicating the length of the list that follows. Assume the list will contain a maximum of 20 integers. Output "yes" if the list is a palindrome and "no" otherwise. The output ends with a newline.
Hints: - use a for loop to populate the array based on the specified size (the first number entered)
- use a for loop to check first value with last value, second value with second from end, etc.
- if the values do not match, set a Boolean variable to flag which statement to output (yes or no)
Ex: If the input is (remember to include spaces between the numbers):
6 1 5 9 9 5 1
the output is:
yes
Ex: If the input is:
5 1 2 3 4 5
the output is: C++ coding
Chapter 16 Solutions
EBK BUSINESS DRIVEN TECHNOLOGY
Ch. 16 - Prob. 1OCCh. 16 - Prob. 2OCCh. 16 - Prob. 1CQCh. 16 - Prob. 2CQCh. 16 - Prob. 3CQCh. 16 - Prob. 4CQCh. 16 - Prob. 5CQCh. 16 - Prob. 1RQCh. 16 - Prob. 2RQCh. 16 - Prob. 3RQ
Ch. 16 - Prob. 4RQCh. 16 - Prob. 5RQCh. 16 - Prob. 6RQCh. 16 - Prob. 7RQCh. 16 - Prob. 8RQCh. 16 - Prob. 9RQCh. 16 - Prob. 10RQCh. 16 - Prob. 4MBDCh. 16 - Prob. 5MBDCh. 16 - Prob. 6MBDCh. 16 - Prob. 7MBDCh. 16 - Prob. 8MBDCh. 16 - Prob. 1CCOCh. 16 - Prob. 2CCOCh. 16 - Prob. 3CCOCh. 16 - Prob. 4CCOCh. 16 - Prob. 5CCOCh. 16 - Prob. 1CCTCh. 16 - Prob. 2CCTCh. 16 - Prob. 3CCTCh. 16 - Prob. 4CCTCh. 16 - Prob. 5CCTCh. 16 - Prob. 6CCTCh. 16 - Prob. 1AYKCh. 16 - Prob. 2AYKCh. 16 - Prob. 4AYKCh. 16 - Prob. 5AYKCh. 16 - Prob. 6AYKCh. 16 - Prob. 7AYKCh. 16 - Prob. 8AYK
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