A stepwise mechanism for the reaction between benzyl bromide and CH 3 OH to afford benzyl methyl ether is to be drawn and an explanation for the reaction of this 1 ° alkyl halide with a weak nucleophile under conditions that favor an S N 1 mechanism is to be stated. The reactivity of given para-substituted benzylic halides is more or less than benzyl bromide is to be predicted and explained. Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Question

Want to see the full answer?

Answer 1

Question

Chapter 16, Problem 66P

Interpretation Introduction

Interpretation: A stepwise mechanism for the reaction between benzyl bromide and CH3OH to afford benzyl methyl ether is to be drawn and an explanation for the reaction of this 1° alkyl halide with a weak nucleophile under conditions that favor an SN1 mechanism is to be stated. The reactivity of given para-substituted benzylic halides is more or less than benzyl bromide is to be predicted and explained.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Decide whether these proposed Lewis structures are reasonable. proposed Lewis structure Is the proposed Lewis structure reasonable? Yes. :0: Cl C C1: 0=0: : 0 : : 0 : H C N No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* ☐ Yes. No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* Yes. ☐ No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | * If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0".

Draw the Lewis structure for the polyatomic trisulfide anion. Be sure to include all resonance structures that satisfy the octet rule. с [ ] - G

1. Calculate the accurate monoisotopic mass (using all 1H, 12C, 14N, 160 and 35CI) for your product using the table in your lab manual. Don't include the Cl, since you should only have [M+H]*. Compare this to the value you see on the LC-MS printout. How much different are they? 2. There are four isotopic peaks for the [M+H]* ion at m/z 240, 241, 242 and 243. For one point of extra credit, explain what each of these is and why they are present. 3. There is a fragment ion at m/z 184. For one point of extra credit, identify this fragment and confirm by calculating the accurate monoisotopic mass. 4. The UV spectrum is also at the bottom of your printout. For one point of extra credit, look up the UV spectrum of bupropion on Google Images and compare to your spectrum. Do they match? Cite your source. 5. For most of you, there will be a second chromatographic peak whose m/z is 74 (to a round number). For one point of extra credit, see if you can identify this molecule as well and confirm by…