For the given titration curve of a weak base with a strong acid, The pH and the added volume of the base at the equivalence point is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the weak acid. The volume of added acid at which p H = 14 − p K b is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the conjugate acid. The volume of added acid is to be determined beyond which the volume of added acid is the pH calculated by concentrating on the amount of excess added strong acid.
For the given titration curve of a weak base with a strong acid, The pH and the added volume of the base at the equivalence point is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the weak acid. The volume of added acid at which p H = 14 − p K b is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the conjugate acid. The volume of added acid is to be determined beyond which the volume of added acid is the pH calculated by concentrating on the amount of excess added strong acid.
Interpretation: For the given titration curve of a weak base with a strong acid,
The pH and the added volume of the base at the equivalence point is to be determined.
The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and Ka of the weak acid.
The volume of added acid at which pH=14−pKb is to be determined.
The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and Ka of the conjugate acid.
The volume of added acid is to be determined beyond which the volume of added acid is the pH calculated by concentrating on the amount of excess added strong acid.
When two solutions, one of 0.1 M KCl (I) and the other of 0.1 M MCl (II), are brought into contact by a membrane. The cation M cannot cross the membrane. At equilibrium, x moles of K+ will have passed from solution (I) to (II). To maintain the neutrality of the two solutions, x moles of Cl- will also have to pass from I to II. Explain this equality: (0.1 - x)/x = (0.1 + x)/(0.1 - x)
Calculate the variation in the potential of the Pt/MnO4-, Mn2+ pair with pH, indicating the value of the standard potential. Data: E0 = 1.12.
Given the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt. Calculate the emf of the cell as a function of pH.
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