Explanation Given The pH of an aqueous solution of NaOH is 11.50 . The pOH of NaOH solution is calculated by the formula, pH + pOH = 14 pOH = 14 − pH Where, pOH is the negative logarithm in the base 10 of [ OH − ] . pH is the negative logarithm in the base 10 of [ H + ] . Substitute the value of pH in the above formula. pOH = 14 − 11.50 = 2

Chemistry: The Central Science (14th Edition)

14th Edition

ISBN: 9780134414232

Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus

Publisher: PEARSON

See similar textbooks

Concept explainers

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibri…

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Videos

Question

Chapter 16, Problem 47E

Interpretation Introduction

To determine: The concentration of an aqueous solution of NaOH that has a pH of 11.50 .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 16, Problem 46E

Chapter 16, Problem 48E

Students have asked these similar questions

pls help on all, inlcude all steps.

19. Complete the following chart for the incorrect electron configurations shown in the left column. When drawing the correct electron configuration, assume the same number of electrons that were shown in the incorrect configuration. Incorrect Electron Configuration 2p ↑↓ ↑ 2s ↑↓ 1s ↑↓↓ ਵੇ ਵੇ ਵੇ 3p ↑ ↑ ↑ - 38 ↑ 2p 2s ↑↓ 1s 2p 2s 1s ** ↑↓ ↑↓ ↑↑ 리리리 Which principle or rule is violated? Explain the violated principle or rule in your own words Draw the correct electron configuration

14.36 Draw all reasonable resonance structures for each compound. a. + b. C. :O: d. :O: NH2 NH2 :O:

Chapter 16 Solutions

Chemistry: The Central Science (14th Edition)

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.