Explanation Given information: y = sinh x and y = cosh x Formula used: The derivative of sinh x is cosh x The derivative of cosh x i s sinh x Calculation: In order to determine where y = sinh x and y = cosh x are increasing and decreasing, Need to take the derivatives of each function. Consider y = sinh x y = sinh x y ' = cosh x cosh x = 0 x = D N E We cannot find a critical point here. However, the derivative is always positive, so we know that the function is increasing over its entire domain

Loose-leaf Version For Calculus: Early Transcendentals

4th Edition

ISBN: 9781319055912

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Chapter 1.6, Problem 38E

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The values of x are y=sinhx and y=coshx increasing and decreasing.

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Chapter 1.6, Problem 37E

Chapter 1.6, Problem 39E

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Chapter 1 Solutions

Loose-leaf Version For Calculus: Early Transcendentals

Ch. 1.1 - Prob. 1PQ Ch. 1.1 - Prob. 2PQ Ch. 1.1 - Prob. 3PQ Ch. 1.1 - Prob. 4PQ Ch. 1.1 - Prob. 5PQ Ch. 1.1 - Prob. 6PQ Ch. 1.1 - Prob. 7PQ Ch. 1.1 - Prob. 8PQ Ch. 1.1 - Prob. 9PQ Ch. 1.1 - Prob. 10PQ

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The values of x are y = sinh x and y = cosh x increasing and decreasing.

Solution Summary: The author explains that the function y=mathrmcoshx is increasing for all positive and decreasing for negative values.

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The values of x are y=sinhx and y=coshx increasing and decreasing.

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Chapter 1 Solutions