Explanation Given information: f ( x ) = 1 x + 1 Formula used: Domain is the range of input value in the given function. Calculation: The graph of f ( x ) = 1 x + 1 The domain of f ( x ) is D = { x : x ≠ − 1 } and let’s solve y = f ( x ) for x in terms of y y = 1 x + 1 ⇔ x + 1 = 1 y Or, x = 1 y − 1 Or, x = 1 − y y

Loose-leaf Version For Calculus: Early Transcendentals

4th Edition

ISBN: 9781319055912

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Chapter 1.5, Problem 12E

To determine

A domain on which f is one to one and a formula for the inverse of f restricted to this domain. Sketch the graphs of f and f−1.

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Chapter 1.5, Problem 11E

Chapter 1.5, Problem 13E

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Chapter 1 Solutions

Loose-leaf Version For Calculus: Early Transcendentals

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A domain on which f is one to one and a formula for the inverse of f restricted to this domain. Sketch the graphs of f and f − 1 .

Solution Summary: The author illustrates how f(x) is invertible on its domain with an inverse function.

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A domain on which f is one to one and a formula for the inverse of f restricted to this domain. Sketch the graphs of f and f−1.

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Chapter 1 Solutions