For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn. Concept introduction: Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate. The allylic carbocation is formed as an intermediate by the addition of proton in the HBr , The Br − (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate. For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation. To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

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Answer 1

Question

Chapter 16, Problem 37PP

Interpretation Introduction

Interpretation:

For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn.

Concept introduction:

Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate.

The allylic carbocation is formed as an intermediate by the addition of proton in the HBr ,

The Br− (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate.

For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation.

To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

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Answer 2

Question

Chapter 16, Problem 37PP

Interpretation Introduction

Interpretation:

For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn.

Concept introduction:

Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate.

The allylic carbocation is formed as an intermediate by the addition of proton in the HBr ,

The Br− (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate.

For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation.

To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

Expert Solution & Answer

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Answer 3

Question

Chapter 16, Problem 37PP

Interpretation Introduction

Interpretation:

For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn.

Concept introduction:

Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate.

The allylic carbocation is formed as an intermediate by the addition of proton in the HBr ,

The Br− (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate.

For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation.

To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 16, Problem 37PP

Interpretation Introduction

Interpretation:

For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn.

Concept introduction:

Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate.

The allylic carbocation is formed as an intermediate by the addition of proton in the HBr ,

The Br− (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate.

For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation.

To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

Expert Solution & Answer

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See solution

Answer 5

Chapter 16, Problem 37PP

Interpretation Introduction

Interpretation:

For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn.

Concept introduction:

Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate.

The allylic carbocation is formed as an intermediate by the addition of proton in the HBr ,

The Br− (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate.

For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation.

To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

Answer 6

Chapter 16, Problem 37PP

Interpretation Introduction

Interpretation:

For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn.

Concept introduction:

Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate.

The allylic carbocation is formed as an intermediate by the addition of proton in the HBr ,

The Br− (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate.

For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation.

To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

Answer 7

Chapter 16, Problem 37PP

Interpretation Introduction

Interpretation:

For the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr , the four products and the mechanism that explains the formation of each product are needed to be drawn.

Concept introduction:

Conjugated Dienes undergoes addition reactions with HBr as similar to simple alkenes addition with HBr , but instead of single carbocation intermediate formation of simple alkenes; dienes will form resonance stabilized allylic carbocation as an intermediate.

The allylic carbocation is formed as an intermediate by the addition of proton in the HBr ,

The Br− (nucleophilic) can attacks in either of the two resonance stabilized carbocation’s in the in the allylic intermediate.

For the Butadiene type dienes, there are four carbons for addition of proton, but at C1 and C4 carbons only forms the allylic carbocation.

To draw: the four products and the mechanism that explains the formation of each product for the 2-ethyl-3-methyl-1,3-cyclohexadiene treated with HBr .

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 16.1 - Prob. 1CC Ch. 16.2 - Prob. 2CC Ch. 16.2 - Prob. 3CC Ch. 16.2 - Prob. 4CC Ch. 16.3 - Draw an energy diagram showing the relative energy...Ch. 16.4 - Prob. 1LTS Ch. 16.4 - Prob. 6PTS Ch. 16.4 - Prob. 7PTS Ch. 16.5 - Prob. 2LTS Ch. 16.5 - Predict the products for each of the following...

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