Way to evaluate the query: Consider a situation, when only top few “K” answers to r | >< | s of relations “r” and “s” with an index of attribute “A” is required. When the join is on a foreign key of relation “r” referencing “s”, An each tuple of relation “r” will join with only one tuple of relation “s”

Question

Explian thiS C program #include<stdio.h> int countSetBits(int n) { int count = 0; while (n) { count += n & 1; n >>= 1; } return count;} int main() { int num; printf("Enter a number: "); scanf("%d", &num); printf("Output: %d units\n", countSetBits(num)); return 0;}

Answer 1

Expert Solution & Answer

Chapter 16, Problem 25E

a.

Explanation of Solution

Way to evaluate the query:

Consider a situation, when only top few “K” answers to r |><| s of relations “r” and “s” with an index of attribute “A” is required.

When the join is on a foreign key of relation “r” referencing “s”,

An each tuple of relation “r” will join with only one tuple of relation “s”

b.

Explanation of Solution

Way to evaluate the query when a join is not on a foreign key:

Consider a situation, when only top few “K” answers to r |><| s of relations “r” and “s” with an index of attribute “B” is required

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

Explian thiS C program #include<stdio.h> int countSetBits(int n) { int count = 0; while (n) { count += n & 1; n >>= 1; } return count;} int main() { int num; printf("Enter a number: "); scanf("%d", &num); printf("Output: %d units\n", countSetBits(num)); return 0;}

Please provide the Mathematica code

Explian this C program code. #include <stdio.h> void binary(unsigned int n) { if (n /2!=0) { binary(n /2); } printf("%d", n %2); } int main() { unsignedint number =33777; unsignedchar character ='X'; printf("Number: %u\n", number); printf("Binary: "); binary(number); printf("\nDecimal: %u\nHexadecimal: 0x%X\n\n", number, number); printf("Character: %c\n", character); printf("ASCII Binary: "); binary(character); printf("\nASCII Decimal: %u\nASCII Hexadecimal: 0x%X\n", character, character); return0; }