Chapter 16, Problem 21E

Interpretation Introduction

Interpretation:

A $\text{250}\text{mL}$ buffer solution is given to be $\text{0}\text{.250}\text{M}$ in acetic acid and $\text{0}\text{.250}\text{M}$ in sodium acetate. The stated questions based on the given data are to be answered.

Concept introduction: The Henderson-Hasselbalch equation that is used to calculate the value of $\text{pH}$ is,

$\text{pH}=-\log K_a+\text{log}\frac{\left[\text{Base}\right]}{\left[\text{Acid}\right]}$

To determine: The pH of the $250\text{ml}$ buffer solution of $0.250\text{M}$ in acetic acid and $0.250\text{M}$ in sodium acetate initially; after addition of $0.0050\text{mol}$ of $\text{HCl}$ and after addition of $0.0050\text{mol}$ of $\text{NaOH}$ .