Chapter 16, Problem 16.64QP

(a)

Interpretation Introduction

Interpretation:

The ${\text{K}}_{\text{b}}$ value for the given ions has to be calculated

Concept Introduction:

Relationship between $K_{a}and{K}_b$

${\text{K}}_{\text{a}}\times {\text{K}}_{\text{b}}{\text{=K}}_{\text{w}}$

Where, ${\text{K}}_{\text{w}}$ is the auto-ionization of water. $(1.0\times {10}^{-14})$

Autoionization of water is the reaction in which the water undergoes ionization to give a proton and a hydroxide ion.  The ionization of water is an equilibrium reaction and hence this has equilibrium rate constant.

$K_w=[{\text{H}}_{\text{3}}{\text{O}}^{+}][{\text{OH}}^{-}]=1.0\times {10}^{-14}$

(b)

Interpretation Introduction

Interpretation:

The ${\text{K}}_{\text{a}}$ value for the given ions has to be calculated

Concept Introduction:

Relationship between $K_{a}and{K}_b$

${\text{K}}_{\text{a}}\times {\text{K}}_{\text{b}}{\text{=K}}_{\text{w}}$

Where, ${\text{K}}_{\text{w}}$ is the auto-ionization of water. $(1.0\times {10}^{-14})$

Autoionization of water is the reaction in which the water undergoes ionization to give a proton and a hydroxide ion.  The ionization of water is an equilibrium reaction and hence this has equilibrium rate constant.

$K_w=[{\text{H}}_{\text{3}}{\text{O}}^{+}][{\text{OH}}^{-}]=1.0\times {10}^{-14}$