Explanation Given Info: The length of the flute is 10.75 cm , the flute is open at one end and closed at other, the fundamental frequency of the string is 600.0 Hz and the speed of the sound in air is 344 m/s . Formula to calculate the condition, at which the flute and string resonance is, ( n flute ) ( f flute ) = ( n string ) ( f string ) (I) n flute is the harmonic at which flute resonance. f flute is the fundamental frequency of the sound. n string is the harmonic at which the string resonance. f string is the fundamental frequency of the string. Formula to calculate the fundamental frequency of the flute is, f flute = v 4 L v is the speed of the sound in air. L is the length of the flute. Substitute 10.75 cm for L and 344 m/s for v in the above equation to find f f l u t e . f flute = ( 344 m/s ) 4 ( 10

13th Edition

ISBN: 9781269542661

Author: YOUNG

Publisher: PEARSON C

See similar textbooks

Concept explainers

Interference of sound

Seiche

A seiche is an oscillating standing wave in a body of water. The term seiche pronounced saysh) can be understood by the sloshing of water back and forth in a swimming pool. The same phenomenon happens on a much larger scale in vast bodies of water includ…

Question

Chapter 16, Problem 16.61P

To determine

The resonance harmonic of the flute and string.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 16, Problem 16.60P

Chapter 16, Problem 16.62P

Students have asked these similar questions

In the pivot assignment, we observed waves moving on a string stretched by hanging weights. We noticed that certain frequencies produced standing waves. One such situation is shown below: 0 ст Direct Measurement ©2015 Peter Bohacek I. 20 0 cm 10 20 30 40 50 60 70 80 90 100 Which Harmonic is this? Do NOT include units! What is the wavelength of this wave in cm with only no decimal places? If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with NO decimal places)?

Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.) A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b. (a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V. 20.0 µF capacitor µC 6.00 µF capacitor µC 3.00 µF capacitor µC capacitor C µC

Two conductors having net charges of +14.0 µC and -14.0 µC have a potential difference of 14.0 V between them. (a) Determine the capacitance of the system. F (b) What is the potential difference between the two conductors if the charges on each are increased to +196.0 µC and -196.0 µC? V

Chapter 16 Solutions

MASTERINGPHYSICS W/ETEXT ACCESS CODE 6

Ch. 16.1 - You use an electronic signal generator to produce...Ch. 16.2 - Mercury is 13.6 times denser than water. Based on...Ch. 16.3 - Prob. 16.3TYU Ch. 16.4 - If you connect a hose to one end of a metal pipe...Ch. 16.5 - A stopped organ pipe of length L has a fundamental...Ch. 16.6 - Suppose that speaker A in Fig. 16.23 emits a...Ch. 16.7 - One tuning fork vibrates at 440 Hz, while a second...Ch. 16.8 - You are at an outdoor concert with a wind blowing...Ch. 16.9 - What would you hear if you were directly behind...Ch. 16 - Prob. 16.1DQ

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The resonance harmonic of the flute and string.

Solution Summary: The author explains how to determine the resonance harmonic of the flute and string.

Concept explainers

The resonance harmonic of the flute and string.

Want to see the full answer?

Chapter 16 Solutions