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Interpretation:
The advantages of plastics as compared to ceramics, glasses and metals are to be stated.
Concept Introduction:
Plastics are materials which are synthesized from a variety of organic polymers like PVC, polyethylene, etc., which can be molded into different shapes while they are soft and then are set into a rigid or slightly elastic material.
Ceramics are the materials that contains inorganic component of metals, non-metal or metalloid atoms which are held in ionic and covalent bonds.
Glasses are non-crystalline material and an amorphous solid which is mostly transparent with widespread practical, technological, and decorative uses.
Metals are materials which shows lustrous appearance when prepared fresh, polished, or fractured. They conduct electricity and heat very well and are malleable and ductile.
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Chapter 16 Solutions
Essentials Of Materials Science And Engineering
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- Generate the kinematic diagram of the following mechanism. Then, draw their graphs and calculate their degrees of freedom (DoF) using Gruebler's formula.arrow_forward8. The thermal decomposition of nitric oxide at elevated temperatures 2NO → N₂+02 has been studied in a batch reactor where at temperatures below 2000K the rate expression that applies to low conversions is: r = kCm05 Co At high conversions, or when the initial mixture contains a high concentration of O2 the rate expression is given by: r = k' Cм0.5 C15C0,5 To explain these kinetics the following chain reaction mechanism has been proposed: Initiation: Propagation: 2NON₂O +0 k₂ E1=272.0 kJ/mol 0+ NO O₂+ N E₂-161.0 kJ/mol N+NO N₂+0 E3-1.4 kJ/mol K4 20+ MO₂+M E4=14.0 kJ/mol ks Termination: where M is any molecule capable of the energy transfer necessary to stabilize the oxygen molecule. Once appreciable amounts of O2 are present in the reaction mixture, the initiation reaction that is the primary source of atomic oxygen is no longer the first reaction. Instead, the following reaction begins to dominate the chain initiation process: Initiation (high O2): ks NO +0₂ NO₂+0 E5=198.0 kJ/mol a.…arrow_forwardCalculate the current magnitude in the coils e1, e2 of theMagnetic circuit, if:ɸa = 3.00 x 10^-3 Wb, φb = 0.80 x 10^-3 Wb, ɸc = 2.20 x 10^-3 Wb L ab = 0.10 m,A ab = 5.0 cm^2L afeb = L acdb = 0.40 mA afeb = A acdb = 20 cm^2 MATERIAL CHARACTERISTICSH (At/m) 240 350 530 1300 5000 9000B (T) 0.7 0.9 1.1 1.3 1.5 1.6arrow_forward
- A toroid magnetic circuit is composed of three sections A, B and C, thesection C has an air gap, section A has an 850 round coil thatconsumes a current of 1.2 A. the physical and magnetic properties of each sectionare: Section A: Length = 80 mm, Cross section = 120 mm^2, μr = 400 Section B: Length = 60 mm, Cross section = 40 mm^2, μr = 250 Section C: Length = 50 mm, Cross section = 200 mm^2, μr = 600 Gap: Length = 1 mm, Cross section = 40 mm^2, μr = 1 Calculate:The magnetic field density in each of the sectionsarrow_forward3) Compute the input impedance of Fig. 3. (10 points) Rin R1 R₂ Figure 3 T Vccarrow_forwardShow the workarrow_forward
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