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(a)
Interpretation:
The molecular weight of the chains for the given polymer is to be calculated.
Concept Introduction:
The molecular weight of a polymer is not fixed. It has a certain range under which its molecular weight falls. For a linear polymer, degree of polymerization represents the average length of the polymer. Degree of polymerization is defined as:
(b)
Interpretation:
The number of chains in the given mass of polymer is to be calculated.
Concept Introduction:
The formula to calculate number of chains in the given mass of polymer is:
Here,
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Chapter 16 Solutions
Essentials Of Materials Science And Engineering
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- Consider a piece of steel undergoing a decarburization process at 925 degrees C. the mass diffusivity of carbon in steel at 925 degrees C is 1*10^-7 cm^2/s. Determine the depth below the surface of the steel at which the concentration of carbon is reduced to 40 percent from its initial value as a result of the decarburization process for (a) an hour and (b) 10 hours. Assume the concnetration of carbon at the surface is zero throughout the decarburization process.arrow_forwardE3.2 Consider the following prototype patterns. i. ii. iii. P1 = P2 = 10.5. [1] Find and sketch a decision boundary for a perceptron network that will recognize these two vectors. Find weights and bias which will produce the decision boundary you found in part i, and sketch the network diagram. Calculate the network output for the following input. Is the network response (decision) reasonable? Explain. p = [2] iv. V. Design a Hamming network to recognize the two prototype vectors above. Calculate the network output for the Hamming network with the input vector given in part iii, showing all steps. Does the Hamming network produce the same decision as the perceptron? Explain why or why not. Which network is better suited to this problem? Explain.arrow_forward7. See the code below and solve the following. public class Test { public static void main(String[] args) { int result = 0; } result = fn(2,3); System.out.println("The result is: + result); // fn(x, 1) = x // fn(x, y) = fn(x, y-1) + 2, when y>1 public static int fn(int x, int y) { if (x <= 1) return x; else return fn(x, y-1) + 2; } } 7-1. This program has a bug that leads to infinite recursion. Modify fn(int x, int y) method to fix the problem. (2 point) 7-2. Manually trace the recursive call, fn(2,3) and show the output (step by step). (2 point) 7-3. Can you identify the Base Case in recursive method fn(int x, int y)? (1 point)arrow_forward
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