Pearson eText Organic Chemistry -- Instant Access (Pearson+)
Pearson eText Organic Chemistry -- Instant Access (Pearson+)
9th Edition
ISBN: 9780135213728
Author: Leroy Wade, Jan Simek
Publisher: PEARSON+
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Chapter 16, Problem 16.34SP

(a)

Interpretation Introduction

Interpretation:

The nature of nitrogen atom in the given heterocyclic compound as strongly basic or weakly basic on the basis of availability of the lone pair of electrons is to be stated.

Concept introduction:

According to Lewis acid-base theory, an acid is a species that accepts the lone pair of electrons while a base is a species that donates the lone pair of electrons.

(b)

Interpretation Introduction

Interpretation:

The nature of nitrogen atom in the given heterocyclic compound as strongly basic or weakly basic on the basis of availability of the lone pair of electrons is to be stated.

Concept introduction:

According to Lewis acid-base theory, an acid is a species that accepts the lone pair of electrons while a base is a species that donates the lone pair of electrons.

(c)

Interpretation Introduction

Interpretation:

The nature of nitrogen atom in the given heterocyclic compound as strongly basic or weakly basic on the basis of availability of the lone pair of electrons is to be stated.

Concept introduction:

According to Lewis acid-base theory, an acid is a species that accepts the lone pair of electrons while a base is a species that donates the lone pair of electrons.

(d)

Interpretation Introduction

Interpretation:

The nature of nitrogen atom in the given heterocyclic compound as strongly basic or weakly basic on the basis of availability of the lone pair of electrons is to be stated.

Concept introduction:

According to Lewis acid-base theory, an acid is a species that accepts the lone pair of electrons while a base is a species that donates the lone pair of electrons.

(e)

Interpretation Introduction

Interpretation:

The nature of nitrogen atom in the given heterocyclic compound as strongly basic or weakly basic on the basis of availability of the lone pair of electrons is to be stated.

Concept introduction:

According to Lewis acid-base theory, an acid is a species that accepts the lone pair of electrons while a base is a species that donates the lone pair of electrons.

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(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³
fcrip = ↓ bandwidth Il temp 32. What impact (increase, decrease, or no change) does each of the following conditions have on the individual components of the van Deemter equation and consequently, band broadening? Increase temperature Longer column Using a gas mobile phase instead of liquid Smaller particle stationary phase Multiple Paths Diffusion Mass Transfer
34. Figure 3 shows Van Deemter plots for a solute molecule using different column inner diameters (i.d.). A) Predict whether decreasing the column inner diameters increase or decrease bandwidth. B) Predict which van Deemter equation coefficient (A, B, or C) has the greatest effect on increasing or decreasing bandwidth as a function of i.d. and justify your answer. Figure 3 Van Deemter plots for hydroquinone using different column inner diameters (i.d. in μm). The data was obtained from liquid chromatography experiments using fused-silica capillary columns packed with 1.0-μm particles. 35 20 H(um) 큰 20 15 90 0+ 1500 100 75 550 01 02 594 05 μ(cm/sec) 30 15 10

Chapter 16 Solutions

Pearson eText Organic Chemistry -- Instant Access (Pearson+)

Ch. 16.8A - Repeat Problem16-10 for the cyclopentadienyl ions....Ch. 16.8C - Explain why each compound or ion should be...Ch. 16.8C - The following hydrocarbon has an unusually large...Ch. 16.8C - Prob. 16.14PCh. 16.8C - Prob. 16.15PCh. 16.9B - Prob. 16.16PCh. 16.9C - Show which of the nitrogen atoms in purine are...Ch. 16.9C - The proton NMR spectrum of 2-pyridone gives the...Ch. 16.9D - Prob. 16.19PCh. 16.9D - Prob. 16.20PCh. 16.10 - Prob. 16.21PCh. 16.12 - Ciprofloxacin is a member of the fluoroquinolone...Ch. 16.13 - Draw and name all the chlorinated benzenes having...Ch. 16.13 - Name the following compounds:Ch. 16.15 - The UV spectrum of 1-phenylprop-2-en-1-ol shows an...Ch. 16 - Prob. 16.26SPCh. 16 - Name the following compounds:Ch. 16 - Draw and name all the methyl, dimethyl, and...Ch. 16 - Four pairs of compounds are shown. In each pair,...Ch. 16 - One of the following hydrocarbons is much more...Ch. 16 - In Kekuls time cyclohexane was unknown, and there...Ch. 16 - Prob. 16.32SPCh. 16 - Azulene is a deep-blue hydrocarbon with resonance...Ch. 16 - Prob. 16.34SPCh. 16 - Prob. 16.35SPCh. 16 - Prob. 16.36SPCh. 16 - Prob. 16.37SPCh. 16 - Prob. 16.38SPCh. 16 - Prob. 16.39SPCh. 16 - Biphenyl has the following structure. a. Is...Ch. 16 - Anions of hydrocarbons are rare, and dianions of...Ch. 16 - How would you convert the following compounds to...Ch. 16 - Prob. 16.43SPCh. 16 - Prob. 16.44SPCh. 16 - A student found an old bottle labeled thymol on...Ch. 16 - Prob. 16.46SPCh. 16 - Prob. 16.47SPCh. 16 - Prob. 16.48SPCh. 16 - The proton NMR chemical shifts of the hydrogens in...Ch. 16 - Prob. 16.50SPCh. 16 - NMR has been used to probe many molecular...
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